What is the average of 8a and 4b? 1. a+b=5 2. 2a+b=11 : DS Archive
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# What is the average of 8a and 4b? 1. a+b=5 2. 2a+b=11

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What is the average of 8a and 4b? 1. a+b=5 2. 2a+b=11 [#permalink]

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20 Nov 2005, 14:30
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Q1. What is the average of 8a and 4b?
1. a+b=5
2. 2a+b=11
VP
Joined: 06 Jun 2004
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20 Nov 2005, 14:34

(8a+4b)/2 ==> 4(2a+b)/2

(1) We do not know the values of a and b. Insufficient.

(2) 2a+b = 11, we know the average is 4(11)/2. Sufficient.
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21 Nov 2005, 00:24
faisalt wrote:
Q1. What is the average of 8a and 4b?
1. a+b=5
2. 2a+b=11

Its B.
Multiply both sides of statemen2 by 4 we get
8a + 4b = 44 Hence the answer.
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21 Nov 2005, 11:40
one more vote for B

Q1. What is the average of 8a and 4b?
1. a+b=5

We need to know the sum of 8a+4b , can not be calculated from a+b. Hence Insuff

2. 2a+b=11

8a+4b= 4(2a+b)=4*11

average 4*11/2

Suff

so B
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23 Nov 2005, 05:09
1. 8a+4b cannot determine a+b in the sum so insufficent

2. 4(2a+b); substitute 11--->4(11)=44 sufficient

(B)
23 Nov 2005, 05:09
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# What is the average of 8a and 4b? 1. a+b=5 2. 2a+b=11

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