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What is the average of 8a and 4b? 1. a+b=5 2. 2a+b=11

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What is the average of 8a and 4b? 1. a+b=5 2. 2a+b=11 [#permalink] New post 20 Nov 2005, 15:30
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Q1. What is the average of 8a and 4b?
1. a+b=5
2. 2a+b=11
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 [#permalink] New post 20 Nov 2005, 15:34
Answer is B.

(8a+4b)/2 ==> 4(2a+b)/2

(1) We do not know the values of a and b. Insufficient.

(2) 2a+b = 11, we know the average is 4(11)/2. Sufficient.
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Re: DS-average [#permalink] New post 21 Nov 2005, 01:24
faisalt wrote:
Q1. What is the average of 8a and 4b?
1. a+b=5
2. 2a+b=11


Its B.
Multiply both sides of statemen2 by 4 we get
8a + 4b = 44 Hence the answer.
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 [#permalink] New post 21 Nov 2005, 12:40
one more vote for B

Q1. What is the average of 8a and 4b?
1. a+b=5

We need to know the sum of 8a+4b , can not be calculated from a+b. Hence Insuff

2. 2a+b=11

8a+4b= 4(2a+b)=4*11

average 4*11/2

Suff

so B
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 [#permalink] New post 23 Nov 2005, 06:09
1. 8a+4b cannot determine a+b in the sum so insufficent

2. 4(2a+b); substitute 11--->4(11)=44 sufficient

(B)
  [#permalink] 23 Nov 2005, 06:09
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What is the average of 8a and 4b? 1. a+b=5 2. 2a+b=11

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