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What is the average of eleven consecutive integers? 1) The [#permalink]
13 Apr 2007, 21:11

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

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What is the average of eleven consecutive integers?

1) The average of the first nine integers is 7.
2) The average of the last nine integers is 9

OA: D

I just setup the equation X/9 = 7, to get X = 63...but then after that I just started plugging in numbers that would add up to 63. Took a bit of time and just wondering if there is another method.

lets say first number in the sequence is X then the sum of first 9consequitive number will be 9X+ 8 but its avg is 7 hence 9X + 8 = 63 so we can get the value of X and hence our answer. 1 is sufficient

Similarly 2 is also sufficient... hence answer is D

Use this formula rather than adding up the consecutive integers:

lets consider the numbers are x, x+1, x+2.....

average of first 7 CONSECUTIVE integers = (First term+last term)/2 = (x +x+6)/2 = 7
solve for x
now the average of 11 integers can be found out. SUFF

Statement2:
The same way, the average of the last 9 CONSECUTIVE integers = [(x+2)+(x+10)]/2 =9
solve for x , average of 11 integers can be found out. SUFF