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What is the average weight of the three new team members who

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What is the average weight of the three new team members who [#permalink] New post 20 Feb 2011, 22:00
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A
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E

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  35% (medium)

Question Stats:

58% (01:56) correct 41% (01:30) wrong based on 36 sessions
What is the average weight of the three new team members who were recently included in the team?

1. The average weight of the team increases by 20 kg
2. The three new men substitute the earlier members whose weights were 64 kg, 75 kg and 66 kg.

The source: http://www.testpreppractice.net
[Reveal] Spoiler: OA

Last edited by Bunuel on 21 Feb 2011, 05:31, edited 1 time in total.
Edited the OA
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Manager
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Re: data suff average [#permalink] New post 20 Feb 2011, 22:54
Let w be original average weight of the team having N members and A be the average weight of the the three new members.

From 1, (w*N+3*A)/(N+3) = w + 20 We cant solve for A till we know N and w, so insufficient

From 2, we just have information about the weight out of the system (205 Kg) and no information on w or N, so cant solve for A, insufficient.

Combining 1 and 2 , we get (w*N-205+3*A)/(N) = w+20 Again, we cant solve for A till we know w and N so insufficient again

Answer E
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Re: data suff average [#permalink] New post 21 Feb 2011, 03:50
Hi

The answer seems to be E. Are you sure it's D ?

Let x be mean of weights and n be the number of people.

=> x*n - Total Weight

From (1) we have :
x + 20 is new mean

(x + 20) (n + 3) - New total weight

[(x+20) (n + 3) - xn]/3

is average weight of 3 people

Not sufficient.

From (2) we have :
x*n - 205 + 3*w = 20*n

Not sufficient.

Even (1) and (2) are not enough, so E.

Could someone please opine on whether I'm correct ?

Regards,
Subhash
_________________

Formula of Life -> Achievement/Potential = k * Happiness (where k is a constant)

Re: data suff average   [#permalink] 21 Feb 2011, 03:50
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