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Re: DS: cube root of w [#permalink]
 09 May 2006, 20:39
M8 wrote: What is the cube root of w?
(1) The 5th root of w is 64.
(2) The 15th root of w is 4.
(1) w^1/5 = 64
w^(1/5)(5) = 64^5
w = 64^5
w = (4^15)
w^1/3 = 4^(1/3)(15)
w^1/3 = 4^5
(2) w^1/15 = 4
w = 4^15
w^1/3 = 4^(1/3)(15)
w^1/3 = 4^5
so D...
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Director
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Thanks for your explanation guys the OA is 'D'.
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What is the cube root of w? (1) The 5th root of w is 64. (2) The 15th root of w is 4.
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do we need to do calculation for this...... each statement is enough to have the value for W.
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Re: DS: cube root of w [#permalink]
27 Oct 2010, 00:16
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Manager
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Re: DS: cube root of w [#permalink]
17 Apr 2011, 09:12
Both 1 and 2 essentially give us data to find the number by themselves. So D.
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Re: DS: cube root of w [#permalink]
17 Apr 2011, 09:23
(w)^1/5 = 4^3 w = (4^3)^5 = 4^15 (w)^1/3 = 4^5 Sufficient (2) (w)^1/15 = 4 w = 4^15 (w)^1/3 = 4^5 Sufficient Answer - D
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Re: DS: cube root of w [#permalink]
22 Apr 2011, 18:37
1. Sufficient to find out w and hence sufficient to find cube root of w.
2.Sufficient to find out w and hence sufficient to find cube root of w.
Answer is D.
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What is the cube root of w ?
(1) The 5th root of w is 64.
(2) The 15th root of w is 4.
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
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a w^(1/5) = 64 w = 64^5 = (4^3)^5 w^(1/3) = 4^5 Hence sufficient. b w^(1/15) = 4 w = 4^ 15 w^(1/3) = 4^5. Hence sufficient. D.
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