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Gmat Hacks Challenge Problem found in the Data Sufficiency Challenge set, I thought the answer was "C" because if you know OQ than you can draw a line to OA and form a right triangle and than if you have the heigh OP you can find the missing side (AP) which is half of AB.

OA: 34. E Explanation: Most measurements in a circle (radius, diameter, circumference, area) are closely related, but the same is not true of chords. Statement (1) is not sufficient, as knowing the length of the radius tells us nothing about the length of the chord, which could be placed anywhere between the top of the circle and just above the center. Statement (2) is also insufficient even if we know the placement of point P on the radius, theres no way to use that to find the length of the chord.

Taken together, we still have little information about chord AB. Unless the chord is part of a quadrilateral, triangle, or other fi gure, its not possible to find the length of a chord from the measurements of the circle that contains it.

Re: What is the length of chord AB in circle O above? [#permalink]
06 Dec 2012, 04:44

4

This post received KUDOS

What is the length of chord AB in circle O above? (1) OQ = 5 (2) OP = 3

E. Your reference that OQ is perpendicular to AB is incorrect. The perpendicular from center of circle on a chord bisects the chord. Just looking at figure and figuring that it is perpendicular is incorrect.

Re: What is the length of chord AB in circle O above? [#permalink]
06 Dec 2012, 04:46

BangOn wrote:

What is the length of chord AB in circle O above? (1) OQ = 5 (2) OP = 3

E. Your reference that OQ is perpendicular to AB is incorrect. The perpendicular from center of circle on a chord bisects the chord. Just looking at figure and figuring that it is perpendicular is incorrect.

Re: What is the length of chord AB in circle O above? [#permalink]
28 Mar 2014, 08:46

1

This post received KUDOS

Expert's post

joshlevin90 wrote:

could some one explain why you cant make a triangle with the given information to find AB

Not sure which triangle you are taking about...

As for the answer: all we know even when we combine the statements is the radius of the circle (r=OQ=5) and the positioning of point P on OQ (OP=3). We know nothing about the chord AB other than it passes through point P: it can be at any angle to OQ, which gives different values of its length.

Re: What is the length of chord AB in circle O above? [#permalink]
27 Oct 2014, 23:22

Bunuel wrote:

joshlevin90 wrote:

could some one explain why you cant make a triangle with the given information to find AB

Not sure which triangle you are taking about...

As for the answer: all we know even when we combine the statements is the radius of the circle (r=OQ=5) and the positioning of point P on OQ (OP=3). We know nothing about the chord AB other than it passes through point P: it can be at any angle to OQ, which gives different values of its length.

Re: What is the length of chord AB in circle O above? [#permalink]
28 Oct 2014, 02:57

2

This post received KUDOS

Expert's post

vietnammba wrote:

Bunuel wrote:

joshlevin90 wrote:

could some one explain why you cant make a triangle with the given information to find AB

Not sure which triangle you are taking about...

As for the answer: all we know even when we combine the statements is the radius of the circle (r=OQ=5) and the positioning of point P on OQ (OP=3). We know nothing about the chord AB other than it passes through point P: it can be at any angle to OQ, which gives different values of its length.

Attachment:

Untitled.png

Hope it's clear.

Hi Bunuel,

In case OQ bisects AB, is the answer C?

"Bisect" means to divide into two equal parts. So, AB bisects OQ at P, means that OP = PQ = 2.5. In this case the answer would still be E, because the angle at which AB cuts OQ would still be unknown.

But if we were told that AB is perpendicular to OQ, then the answer would be C.

Harvard asks you to write a post interview reflection (PIR) within 24 hours of your interview. Many have said that there is little you can do in this...