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What is the length of the chord AB [#permalink]
 29 Jan 2012, 23:52
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87% (01:40) correct
12% (02:05) wrong based on 0 sessions
What is the length of the chord AB (1) The center of the circle is at the Origin and the chord AB is parallel to y-axis with one end of it at (8,6) (2) The equation of the circle is x^2 + y^2 = 100
Last edited by Bunuel on 30 Jan 2012, 03:14, edited 1 time in total.
Topic moved to DS subforum.
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Re: Co-ordinate Geometry DS - Please explain [#permalink]
30 Jan 2012, 00:14
Yes, the question asks for chord not arc.
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Re: Co-ordinate Geometry DS - Please explain [#permalink]
30 Jan 2012, 00:17
Sorry, I'm new to this. Is this for fun or did you want help with the problem?
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Re: Co-ordinate Geometry DS - Please explain [#permalink]
30 Jan 2012, 00:32
Answer has to be A. It is parallel to y axis and we already know its length on top of the x-axis, i.e. 6. Now since the chord will mirror on the other side of x-axis, i.e when y is negative, we can double 6 to get the length of the chord, which will be 12 . We do not need the size of the circle and the size of the circle itself will not be sufficient. Hence the answer has to be A.
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Re: Co-ordinate Geometry DS - Please explain [#permalink]
30 Jan 2012, 00:48
A is sufficient Statement A : It is given that the center of the circle is 0 (0,0) & 1 end point of the Chord AB A (8,6). Further AB is parallel to the Y - Axis. From the above we can form the triangle AOB with height of 6 & base of 8. Using Pytha theorem we can find the Hypoth OA which is the radius. From this it is possible to find the coordinates of B using Pythag theorem Thus Sufficient Statement B : From the eqn of circle we can only compute the radius of circle which is 10 & thus is insufficient Hope this helps 
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Re: Co-ordinate Geometry DS - Please explain [#permalink]
30 Jan 2012, 00:52
boomtangboy wrote: A is sufficient Statement A : It is given that the center of the circle is 0 (0,0) & 1 end point of the Chord AB A (8,6). Further AB is parallel to the Y - Axis. From the above we can form the triangle AOB with height of 6 & base of 8. Using Pytha theorem we can find the Hypoth OA which is the radius. From this it is possible to find the coordinates of B using Pythag theorem Thus Sufficient Statement B : From the eqn of circle we can only compute the radius of circle which is 10 & thus is insufficient Hope this helps Why do you need to use the pythagorean theorem. Its pretty simple as it is. 8,6 means one half is 6 units long since it is parallel to y axis. Just double (since the circle is centered at origin) 6*2=12 which is the length of the cord. Had it not been parallel to the y-axis, it was a whole different story altogether and pythagorean theorem could have come in.
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Re: Co-ordinate Geometry DS - Please explain [#permalink]
30 Jan 2012, 03:12
Topic moved to DS subforum.kenguva wrote: What is the length of the chord AB
(1) The center of the circle is at the Origin and the chord AB is parallel to y-axis with one end of it at (8,6)
(2) The equation of the circle is x^2 + y^2 = 100 What is the length of the chord AB(1) The center of the circle is at the Origin and the chord AB is parallel to y-axis with one end of it at (8,6) --> as the circle is centered at the origin and chord AB is parallel to y-axis then the other end of the chord will be mirror reflection around x-axis: Attachment: 
1.PNG [ 12.79 KiB | Viewed 601 times ]
So, the length of AB=12. Sufficient (2) The equation of the circle is x^2 + y^2 = 100 --> just gives us an equation of a circle centered at the origin with radius equal to 10. No info about the chord. Not sufficient. Answer: A. For more on this topic check Coordinate Geometry chapter of Math Book: math-coordinate-geometry-87652.htmlP.S. Please post PS questions in the PS subforum: gmat-problem-solving-ps-140/Please post DS questions in the DS subforum: gmat-data-sufficiency-ds-141/No posting of PS/DS questions is allowed in the main Math forum.
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Re: Co-ordinate Geometry DS - Please explain
[#permalink]
30 Jan 2012, 03:12
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