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What is the mean of four consecutive even integers a , b , c [#permalink ]
25 Oct 2009, 10:53

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What is the mean of four consecutive even integers a , b , c , d ? 1. a + d = b + c 2. b + c = d - a

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Re: even consecutive [#permalink ]
25 Oct 2009, 10:56

Is there something missing in the Q? I didn't understand the Q

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Re: even consecutive [#permalink ]
25 Oct 2009, 11:13

Nopes, question is correct

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Re: even consecutive [#permalink ]
25 Oct 2009, 18:36

Is C the OA? Since they are 4 even consecutive integers , b, c, d can be represented as a+2, a+4, a+6 resp So mean is a+a+2+a+4+a+6 divided by 4 => a+3 ------> eqn 1 Now 1) a+d = b+c which means Mean = a+b+c+d divided by 4 => b+c divided by 2 We know nothing about a or any number. So insuff Now from 2) b+c = d-a We get Mean = d/2 which yields nothing - so insuff Together a+d = b+c and b+c = d-a equating the two above we get a+d = d-a or 2a = 0 a =0 Hence we get a From eqn ---->1 we know Mean = a+3 Hence Mean = 0+3 = 3 Sufficient by both 1 and 2 Correct me if I am wrong. Would appreciate it

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Re: even consecutive [#permalink ]
25 Oct 2009, 18:47

IMO B

What is the mean of four consecutive even integers a , b , c , d ?

1. a + d = b + c

2. b + c = d - a

lets assume the numbers as a, a+2, a+4, a+6 since they are four consecutive integers

S1 ) given that a+d = b+c

2a +6 = 2a + 6 - no new information is given that is different from question stem - insufficient

S2) given that b+c = d-a

==>

a+2+a+4 = a+6-a

2a+6 =6 ==> a = 0, so the numbers are 0, 2,4,6 and we can calculate mean - sufficient.Hence

Answer B

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Re: even consecutive [#permalink ]
25 Oct 2009, 18:52

srini123 wrote:

IMO B What is the mean of four consecutive even integers a , b , c , d ? 1. a + d = b + c 2. b + c = d - a lets assume the numbers as a, a+2, a+4, a+6 since they are four consecutive integers S1 ) given that a+d = b+c 2a +6 = 2a + 6 - no new information is given that is different from question stem - insufficient S2) given that b+c = d-a ==> a+2+a+4 = a+6-a 2a+6 =6 ==> a = 0, so the numbers are 0, 2,4,6 and we can calculate mean - sufficient.Hence Answer B

Yeah I think this is the answer. I did not think about it though. Nice catch Sri

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Re: even consecutive [#permalink ]
26 Oct 2009, 01:33

Answer is B.

Question: The stem does not specify the order of elements. it can d<a<b<c or a<b<c<d...does the solution hold true in both the cases? I am lazy to calculate today

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Re: even consecutive [#permalink ]
26 Oct 2009, 08:23

Order not known..imo c..

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Re: even consecutive [#permalink ]
26 Oct 2009, 09:48

What is the mean of four consecutive even integers a , b , c , d ?

1. a + d = b + c

2. b + c = d - a

If we don't know the order of ab,c,d i think the answer would be E

from S1 and S2 all we know is a=0

if the order was d,c,b,a then numbers are -6,-4,-2,0 and mean is -4

if the order was a,b,c,d then numbers are 0,2,4,6 and mean is 4

still both together are not sufficient. hence E

is this right ?

what is OA ?

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Re: even consecutive
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26 Oct 2009, 09:48

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