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What is the mean of four consecutive even integers a , b , c [#permalink]
 25 Oct 2009, 11:53
Question Stats:
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What is the mean of four consecutive even integers a , b , c , d ?
1. a + d = b + c
2. b + c = d - a
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Re: even consecutive [#permalink]
25 Oct 2009, 11:56
Is there something missing in the Q? I didn't understand the Q
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Re: even consecutive [#permalink]
25 Oct 2009, 12:13
Nopes, question is correct
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Re: even consecutive [#permalink]
25 Oct 2009, 19:36
Is C the OA?
Since they are 4 even consecutive integers , b, c, d can be represented as a+2, a+4, a+6 resp
So mean is a+a+2+a+4+a+6 divided by 4 => a+3 ------> eqn 1
Now 1)
a+d = b+c
which means Mean = a+b+c+d divided by 4 => b+c divided by 2
We know nothing about a or any number. So insuff
Now from 2)
b+c = d-a
We get Mean = d/2 which yields nothing - so insuff
Together
a+d = b+c and
b+c = d-a
equating the two above we get
a+d = d-a or
2a = 0
a =0
Hence we get a
From eqn ---->1 we know Mean = a+3
Hence Mean = 0+3 = 3
Sufficient by both 1 and 2
Correct me if I am wrong. Would appreciate it
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Re: even consecutive [#permalink]
25 Oct 2009, 19:47
IMO B What is the mean of four consecutive even integers a , b , c , d ? 1. a + d = b + c 2. b + c = d - a lets assume the numbers as a, a+2, a+4, a+6 since they are four consecutive integers S1 ) given that a+d = b+c 2a +6 = 2a + 6 - no new information is given that is different from question stem - insufficient S2) given that b+c = d-a ==> a+2+a+4 = a+6-a 2a+6 =6 ==> a = 0, so the numbers are 0, 2,4,6 and we can calculate mean - sufficient.Hence Answer B
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Re: even consecutive [#permalink]
25 Oct 2009, 19:52
srini123 wrote: IMO B
What is the mean of four consecutive even integers a , b , c , d ?
1. a + d = b + c
2. b + c = d - a
lets assume the numbers as a, a+2, a+4, a+6 since they are four consecutive integers
S1 ) given that a+d = b+c
2a +6 = 2a + 6 - no new information is given that is different from question stem - insufficient
S2) given that b+c = d-a
==>
a+2+a+4 = a+6-a
2a+6 =6 ==> a = 0, so the numbers are 0, 2,4,6 and we can calculate mean - sufficient.Hence
Answer B Yeah I think this is the answer. I did not think about it though. Nice catch Sri
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Re: even consecutive [#permalink]
26 Oct 2009, 02:33
Answer is B. Question: The stem does not specify the order of elements. it can d<a<b<c or a<b<c<d...does the solution hold true in both the cases? I am lazy to calculate today 
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Re: even consecutive [#permalink]
26 Oct 2009, 09:23
Order not known..imo c..
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Re: even consecutive [#permalink]
26 Oct 2009, 10:48
What is the mean of four consecutive even integers a , b , c , d ? 1. a + d = b + c 2. b + c = d - a If we don't know the order of ab,c,d i think the answer would be E from S1 and S2 all we know is a=0 if the order was d,c,b,a then numbers are -6,-4,-2,0 and mean is -4 if the order was a,b,c,d then numbers are 0,2,4,6 and mean is 4 still both together are not sufficient. hence E is this right ? what is OA ?
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Re: even consecutive
[#permalink]
26 Oct 2009, 10:48
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