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What is the median number of employees assigned per project

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What is the median number of employees assigned per project [#permalink] New post 10 Jan 2006, 19:35
What is the median number of employees assigned per project for the projects at Company Z?

(1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project.

(2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.



:twisted: I think E.. But answer is C...

Why?? T.T
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 [#permalink] New post 10 Jan 2006, 19:52
Median = Middle Number of the Set.

(1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project.

- We do not know the other 75%, insufficient.

(2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project.

- We do not know the other 65%, insufficient.

(1) & (2)

25% of the projects are assigned with 4 or more, indicating 4, 5, 6, ...
35% of the projects are assigned with 2 or fewer, indicating 2, 1, 0

What is left over is that there are 40% of projects with 3 employees assigned to it.

35% are 2, 1, 0.

so, 35%+40% = 75%, which passed 50%, so, we know the median number is 3.
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 [#permalink] New post 10 Jan 2006, 20:42
C.

Coolfish, well illustrated !
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 [#permalink] New post 10 Jan 2006, 21:28
C.

I thought the same way as coolfish did.
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Wow~! [#permalink] New post 11 Jan 2006, 22:05
Thank you for your kind solution.

Have a goodtime~*^^*
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 [#permalink] New post 11 Jan 2006, 22:24
Lets say total projects are 100.
There can be 3 sets
Project having less or equal to 2 employees
Projects having 4 or more employees
and Projects having more than 2 and less than 4 i.e 3 employees

a) 25% of projects have 4 or more... means last 25% have 4 or more..But to find median we need to find the ProjectNo 50.. Insuffcient
b)35% of proj have equal to or less than 2..means first 35 come among this..Still Insufficent

Combina dn u get tht projects from 35....(100-25=75) have 3 employees
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 [#permalink] New post 02 Mar 2006, 12:37
andy_gr8 wrote:
Lets say total projects are 100.
There can be 3 sets
Project having less or equal to 2 employees
Projects having 4 or more employees
and Projects having more than 2 and less than 4 i.e 3 employees

a) 25% of projects have 4 or more... means last 25% have 4 or more..But to find median we need to find the ProjectNo 50.. Insuffcient
b)35% of proj have equal to or less than 2..means first 35 come among this..Still Insufficent

Combina dn u get tht projects from 35....(100-25=75) have 3 employees


I am totally lost ..... why are we assuming that the third set is = Projects having more than 2 and less than 4 i.e 3 employees.


It can be some arbit set
The remaining 40% projects could have --
6 or more/x or more / x or less employees working

Please explain.

Thanks
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 [#permalink] New post 02 Mar 2006, 21:00
Riuscita wrote:
andy_gr8 wrote:
Lets say total projects are 100.
There can be 3 sets
Project having less or equal to 2 employees
Projects having 4 or more employees
and Projects having more than 2 and less than 4 i.e 3 employees

a) 25% of projects have 4 or more... means last 25% have 4 or more..But to find median we need to find the ProjectNo 50.. Insuffcient
b)35% of proj have equal to or less than 2..means first 35 come among this..Still Insufficent

Combina dn u get tht projects from 35....(100-25=75) have 3 employees


I am totally lost ..... why are we assuming that the third set is = Projects having more than 2 and less than 4 i.e 3 employees.


It can be some arbit set
The remaining 40% projects could have --
6 or more/x or more / x or less employees working

Please explain.

Thanks
6 or more is already inclusive in the 4 or more set.
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 [#permalink] New post 13 Jul 2006, 09:53
It's little late but I'm taking E.

(1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project.
(2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project.


(1) 4 or more employees are assigned to 25 percent of the projects at Company Z .
(2) 2 or fewer employees are assigned to 35 percent of the projects at Company Z .


you guys think blue is the same as red??
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 [#permalink] New post 13 Jul 2006, 22:31
C makes sense.

From 1) we know 0,1,2 make up 25%
From 2) we know 4,5,6.. make up 35%

The rest has to be 3 .

If you take 100 projects.
1..........25..26.......65.......100

Median would be Number of employess in 49th + 50th/2

Hence 3+3/2 = 3
  [#permalink] 13 Jul 2006, 22:31
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