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Re: What is the minimum percentage increase in the mean of set X [#permalink]
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pappueshwar wrote:
hi Bunuel,

request to let me if two smallest primes numbers can be negative?


Only positive numbers can be primes, so the smallest prime is 2.

Hope it helps.
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Re: What is the minimum percentage increase in the mean of set X [#permalink]
1 is not a prime number, got to know it now..... was considering it & made the answer wrong :(
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Re: What is the minimum percentage increase in the mean of set X [#permalink]
rohitgoel15 wrote:
What is the minimum percentage increase in the mean of set X {-4, -1, 0, 6, 9} if its two smallest elements are replaced with two different primes?
(A) 25%
(B) 50%
(C) 75%
(D) 100%
(E) 200%


Current mean is =\(\frac{(-4)+(-1)+(0)+(6)+(9)}{5} = \frac{(-5+15)}{5} = \frac{10}{5} = 2\)

Since we have to find the minimum increase , we should add the smallest distinct prime 2,3
New mean is =\(\frac{(0)+(2)+(3)+(6)+(9)}{5} = \frac{20}{5} = 4\)

Percent change = \(\frac{(New -Old}{Old})* 100 = \frac{4-2}{2}*100\)

Percent change = \(\frac{2}{2}* 100 = 100\) %

Answer is D
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What is the minimum percentage increase in the mean of set X [#permalink]
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As others have demonstrated, the average of set X increases from 2 to 4
Many students will incorrectly conclude that we have a 200% increase, since 4 is equal to 2 times 2.
This is not the case.
Percent increase = 100(new - old)/old
So, in this case, percent increase = 100(4 - 2)/2
= 200/2
= 100


Cheers,
Brent

Originally posted by BrentGMATPrepNow on 17 Sep 2016, 04:45.
Last edited by BrentGMATPrepNow on 05 Apr 2020, 10:06, edited 1 time in total.
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Re: What is the minimum percentage increase in the mean of set X [#permalink]
Bunuel
answer will change if I have 5 & 2 or say 2 & 11, isn't it?
just curious...
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Re: What is the minimum percentage increase in the mean of set X [#permalink]
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paidlukkha wrote:
Bunuel
answer will change if I have 5 & 2 or say 2 & 11, isn't it?
just curious...


Yes, it will change but notice that we have to determine the minimum change and for that we are taking the lowest possible values as 2 and 3.
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What is the minimum percentage increase in the mean of set X {-4, -1, [#permalink]
What is the minimum percentage increase in the mean of set X {-4, -1, 0, 6, 9} if its two smallest elements are replaced with two different primes?
(A) 25% (B) 50% (C) 75% (D) 100% (E) 200%

Stuck with above problem looking for some guidance and assistance.
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Re: What is the minimum percentage increase in the mean of set X {-4, -1, [#permalink]
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I think D.
Mean in the initial set is 2 (-4-2+0+6+9)/5. We should replace the smallest elements -4 and -1 with prime numbers also the smallest in order to have minimum percentage increase. So we get new set (2,3,0,6,9) with mean 4. So the minimum % increase is 100%

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Re: What is the minimum percentage increase in the mean of set X [#permalink]
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anairamitch1804 wrote:
What is the minimum percentage increase in the mean of set X {-4, -1, 0, 6, 9} if its two smallest elements are replaced with two different primes?
(A) 25% (B) 50% (C) 75% (D) 100% (E) 200%

Stuck with above problem looking for some guidance and assistance.


Merging topics. Please refer to the discussion above.
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Re: What is the minimum percentage increase in the mean of set X [#permalink]
rohitgoel15 wrote:
What is the minimum percentage increase in the mean of set X {-4, -1, 0, 6, 9} if its two smallest elements are replaced with two different primes?
(A) 25%
(B) 50%
(C) 75%
(D) 100%
(E) 200%


minimize set [2, 3, 0 ,6, 9] = 20/5= 4

old set [-4,-1,0,6,9] = 10/5 =2

4-2/2 = 1

D
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Re: What is the minimum percentage increase in the mean of set X [#permalink]
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Re: What is the minimum percentage increase in the mean of set X [#permalink]
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