Bunuel wrote:

What is the number of cans that can be packed in a certain carton?

(1) The interior volume of this carton is 2,304 cubic inches. No information about the cans. Not sufficient.

(2) The exterior of each can is 6 inches high and has a diameter of 4 inches. No information about the cans. Not sufficient.

(1)+(2) If the dimensions of the carton are 1 by 1 by 2,304, then zero cylindrical cans can be packed in the carton but if the dimensions of the carton are 12 by 12 by 16, then more than zero cylindrical cans can be packed in the carton. Not sufficient.

Answer: E.

Hi Bunuel,

Your statement (2) does not make sense to me. Should it say this instead?

(2) The exterior of each can is 6 inches high and has a diameter of 4 inches. No information about the

~~cans~~ carton. Not sufficient.

My explanation of this problem's solution is:

(1) Not sufficient because you don't have any information about the cans. You would need to know the the volume of each can to figure out how many would "fit" inside the carton.

(2) Not sufficient because you don't have information about the carton these cans are supposed to be packed into.

(1) + (2) Not sufficient because you don't know the exact shape of each can, so it's impossible to calculate the volume in cubic inches. If you knew the shape of the can, i.e. let's say each can is a cylinder shape, then you could use the formula

v=h\pir^2 to calculate the volume of each can in cubic inches. Once you found the volume (in this example, the volume would be

6*(3.14)*2^2\approx 75.36in^3), you can then take the total volume of the carton (

2,304in^3) divided by the volume of each can (

75.36in^3) to figure out that

\approx 30 cans could be packed in/would fit inside the carton.

Hope my logic is correct here,

~ Im2bz2p345