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# What is the number of cans that can be packed in a certain

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What is the number of cans that can be packed in a certain [#permalink]

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07 Dec 2012, 09:53
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What is the number of cans that can be packed in a certain carton?

(1) The interior volume of this carton is 2,304 cubic inches.
(2) The exterior of each can is 6 inches high and has a diameter of 4 inches.
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Re: What is the number of cans that can be packed in a certain [#permalink]

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07 Dec 2012, 09:58
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What is the number of cans that can be packed in a certain carton?

(1) The interior volume of this carton is 2,304 cubic inches. No information about the cans. Not sufficient.
(2) The exterior of each can is 6 inches high and has a diameter of 4 inches. No information about the cartons. Not sufficient.

(1)+(2) If the dimensions of the carton are 1 by 1 by 2,304, then zero cylindrical cans can be packed in the carton but if the dimensions of the carton are 12 by 12 by 16, then more than zero cylindrical cans can be packed in the carton. Not sufficient.

Answer: E.
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Re: What is the number of cans that can be packed in a certain [#permalink]

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04 Jan 2013, 09:21
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Bunuel wrote:
What is the number of cans that can be packed in a certain carton?

(1) The interior volume of this carton is 2,304 cubic inches. No information about the cans. Not sufficient.
(2) The exterior of each can is 6 inches high and has a diameter of 4 inches. No information about the cans. Not sufficient.

(1)+(2) If the dimensions of the carton are 1 by 1 by 2,304, then zero cylindrical cans can be packed in the carton but if the dimensions of the carton are 12 by 12 by 16, then more than zero cylindrical cans can be packed in the carton. Not sufficient.

Answer: E.

If the dimensions had been given instead of volume in 1, it would have been sufficient.
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Re: What is the number of cans that can be packed in a certain [#permalink]

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18 Jul 2013, 03:47
It requires dimensions of the carton and dimenions of the cans in order to determine the number of cans that can be packed into the carton. Since both A and B together doesn't give all of these required dimensions, the answer is E.

For those who like the approach of proving that more than one answer is possible, here is that approach:
Stm A)
Volume of carton is given as 2304.
So sides can be 1*1*2304 or 2*1*1152 leading to more than one answer. Hence insufficient.
Stm B)
Volume of carton can be 1 or 10 or 100. In each case it can accomodate different number of cans leading to more than one answer. Hence insufficient.
Stms A and B Together:
Same explanation given under Stm A holds good. Hence insufficient.
Answer is E.
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Re: What is the number of cans that can be packed in a certain [#permalink]

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18 Jul 2013, 10:52
Bunuel wrote:
What is the number of cans that can be packed in a certain carton?

(1) The interior volume of this carton is 2,304 cubic inches. No information about the cans. Not sufficient.
(2) The exterior of each can is 6 inches high and has a diameter of 4 inches. No information about the cans. Not sufficient.

(1)+(2) If the dimensions of the carton are 1 by 1 by 2,304, then zero cylindrical cans can be packed in the carton but if the dimensions of the carton are 12 by 12 by 16, then more than zero cylindrical cans can be packed in the carton. Not sufficient.

Answer: E.

Hi Bunuel,

Your statement (2) does not make sense to me. Should it say this instead?
(2) The exterior of each can is 6 inches high and has a diameter of 4 inches. No information about the cans carton. Not sufficient.

My explanation of this problem's solution is:

(1) Not sufficient because you don't have any information about the cans. You would need to know the the volume of each can to figure out how many would "fit" inside the carton.

(2) Not sufficient because you don't have information about the carton these cans are supposed to be packed into.

(1) + (2) Not sufficient because you don't know the exact shape of each can, so it's impossible to calculate the volume in cubic inches. If you knew the shape of the can, i.e. let's say each can is a cylinder shape, then you could use the formula $$v=h$$$$\pi$$$$r^2$$ to calculate the volume of each can in cubic inches. Once you found the volume (in this example, the volume would be $$6*(3.14)*2^2$$$$\approx 75.36in^3$$), you can then take the total volume of the carton ($$2,304in^3$$) divided by the volume of each can ($$75.36in^3$$) to figure out that $$\approx 30$$ cans could be packed in/would fit inside the carton.

Hope my logic is correct here,

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Re: What is the number of cans that can be packed in a certain [#permalink]

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18 Jul 2013, 10:56
Im2bz2p345 wrote:
Bunuel wrote:
What is the number of cans that can be packed in a certain carton?

(1) The interior volume of this carton is 2,304 cubic inches. No information about the cans. Not sufficient.
(2) The exterior of each can is 6 inches high and has a diameter of 4 inches. No information about the cans. Not sufficient.

(1)+(2) If the dimensions of the carton are 1 by 1 by 2,304, then zero cylindrical cans can be packed in the carton but if the dimensions of the carton are 12 by 12 by 16, then more than zero cylindrical cans can be packed in the carton. Not sufficient.

Answer: E.

Hi Bunuel,

Your statement (2) does not make sense to me. Should it say this instead?
(2) The exterior of each can is 6 inches high and has a diameter of 4 inches. No information about the cans carton. Not sufficient.

My explanation of this problem's solution is:

(1) Not sufficient because you don't have any information about the cans. You would need to know the the volume of each can to figure out how many would "fit" inside the carton.

(2) Not sufficient because you don't have information about the carton these cans are supposed to be packed into.

(1) + (2) Not sufficient because you don't know the exact shape of each can, so it's impossible to calculate the volume in cubic inches. If you knew the shape of the can, i.e. let's say each can is a cylinder shape, then you could use the formula $$v=h$$$$\pi$$$$r^2$$ to calculate the volume in cubic inches. Once you found the volume (in this example, the volume would be $$6*(3.14)*2^2$$$$\approx 75.36in^3$$. You can then take the total volume of the carton ($$2,304in^3$$) divided by the volume of each can ($$75.36in^3$$) to figure out that $$\approx 30$$ cans could be packed in/would fit.

Hope my logic is correct here,

~ Im2bz2p345

Wasn't it clear that it was a simple typo? Cans instead of cartons?
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Re: What is the number of cans that can be packed in a certain [#permalink]

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18 Jul 2013, 11:07
Bunuel wrote:
Im2bz2p345 wrote:
Hi Bunuel,

Your statement (2) does not make sense to me. Should it say this instead?
(2) The exterior of each can is 6 inches high and has a diameter of 4 inches. No information about the cans carton. Not sufficient.

Wasn't it clear that it was a simple typo? Cans instead of cartons?

It threw me off in my thinking because I was like "what information about the can is missing?." Maybe the shape of each can? The carton's information is definitely missing, so I had to post to get some clarification.

Hope you're not mad

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Re: What is the number of cans that can be packed in a certain [#permalink]

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15 Sep 2014, 07:05
Got the point!
But in a reversal case where dimension of carton is given, along with the volume of can. Then, can we get to the answer as above??Bunuel
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Re: What is the number of cans that can be packed in a certain [#permalink]

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15 Sep 2014, 20:53
Akashmadaan wrote:
Got the point!
But in a reversal case where dimension of carton is given, along with the volume of can. Then, can we get to the answer as above??Bunuel

No, the answer would still be E (well if the volume of the carton is less than the volume of the cans, then we could say that 0 cans could be placed). The point is that the volume of a can does not limit its height or diameter, so for any volume we can consider the height to be greater than any of the dimensions of the carton, and this would mean that 0 cans could be placed.
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Re: What is the number of cans that can be packed in a certain [#permalink]

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14 Jul 2015, 05:12
To solve this one we need a height of the carton. Neither St1 nor St2 gives us this information even combiden --> (E)
1) l*w*h=2304 what is the Height of the carton? Not Sufficient
2) Can H=6, D=4, we need a height of the carton - If the height is 5 then a can fit there, if the height of the carton is 4 - the answer is NO, the cans don't fit there. Not Sufficient
1+2) We need the height of the carton - Not sufficient (E)
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What is the number of cans that can be packed in a certain [#permalink]

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26 Jun 2016, 04:54
Bunuel wrote:
Akashmadaan wrote:
Got the point!

No, the answer would still be E (well if the volume of the carton is less than the volume of the cans, then we could say that 0 cans could be placed). The point is that the volume of a can does not limit its height or diameter, so for any volume we can consider the height to be greater than any of the dimensions of the carton, and this would mean that 0 cans could be placed.

Bunuel
Hi, I have couple of queries in this question

1) Are we assuming that can is right angled cylinder ?

2) Even if Can is cylinder and we know size and shape of Carton, number of cans in box will be dependent on the arrangement of cans, so answer will be E in any case >
What is the number of cans that can be packed in a certain   [#permalink] 26 Jun 2016, 04:54
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