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What is the perimeter of the rectangle having an area of 105

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What is the perimeter of the rectangle having an area of 105 [#permalink]  01 Nov 2008, 08:14
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What is the perimeter of the rectangle having an area of 105 ?

(1) The length is greater than twice the width
(2) length and width of the rectangle are integers greater than 5
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Re: DS : KAPLAN : Perimeter of rectangle [#permalink]  01 Nov 2008, 08:18
B

lb = 105 = 5*7*3

stmt1: InSuff
stmt2: l>5,b>5 ,so l is either 7 or 21 and viceversa for b
Suff
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Re: DS : KAPLAN : Perimeter of rectangle [#permalink]  01 Nov 2008, 08:56
B it is
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Re: DS : KAPLAN : Perimeter of rectangle [#permalink]  01 Nov 2008, 09:00
amitdgr wrote:
What is the perimeter of the rectangle having an area of 105 ?

(1) The length is greater than twice the width
(2) length and width of the rectangle are integers greater than 5

I think it's E.

1 is obviously insuff.

with 2, the possible values for length and width are 35, 3; 21, 5; 15, 7.
So 2 also is insuff because the perimeters are all different with the different set of values.

Combining 1 and 2 also we are able to eliminate only one option because each integer is > 5 so 35 and 3 is out.

It still leaves us with 2 choices. So E.
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Re: DS : KAPLAN : Perimeter of rectangle [#permalink]  01 Nov 2008, 11:42
105=5*21 or 5*7*3..if each side is greater than 5 and is INTEGER only possibility is 7*15

dwivedys wrote:
amitdgr wrote:
What is the perimeter of the rectangle having an area of 105 ?

(1) The length is greater than twice the width
(2) length and width of the rectangle are integers greater than 5

I think it's E.

1 is obviously insuff.

with 2, the possible values for length and width are 35, 3; 21, 5; 15, 7.
So 2 also is insuff because the perimeters are all different with the different set of values.

Combining 1 and 2 also we are able to eliminate only one option because each integer is > 5 so 35 and 3 is out.

It still leaves us with 2 choices. So E.
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Re: DS : KAPLAN : Perimeter of rectangle [#permalink]  01 Nov 2008, 12:33
How is Stmnt 1 insuff. This is how I see stmnt 1 as being suff. If area = 15* 7 that satisfies the point that length (15) > twice the width (7). Thus, it is sufficient.

Can anyone explain what is that I am missing ???
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Re: DS : KAPLAN : Perimeter of rectangle [#permalink]  01 Nov 2008, 12:35
rnemani wrote:
How is Stmnt 1 insuff. This is how I see stmnt 1 as being suff. If area = 15* 7 that satisfies the point that length (15) > twice the width (7). Thus, it is sufficient.

Can anyone explain what is that I am missing ???

Stamtment 1 also means 15.1 * 6.9 > twice the width (6.9). That is why it is insufficient.
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Re: DS : KAPLAN : Perimeter of rectangle [#permalink]  01 Nov 2008, 12:37
Thanks,
I missed the fact that there is no mention about the length and wodth being an integer
Re: DS : KAPLAN : Perimeter of rectangle   [#permalink] 01 Nov 2008, 12:37
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