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VP
Joined: 13 Jun 2004
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What is the probability of getting at least one six in a [#permalink]
13 Mar 2005, 19:10
What is the probability of getting at least one six in a single throw of three unbiased dice?
(a) 1 / 6
(b) 125 / 216
(c) 1 / 36
(d) 91 / 216
(e) 11 / 38
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GMAT Club Legend
Joined: 07 Jul 2004
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Location: Singapore
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P(getting a 6) = 1/6
P(not getting a 6 on one throw) = 5/6
P (not getting a 6 on three throws) = 5/6*5/6*5/6 = 125/216
P(getting at least a 6) = 1-125/216= 91/216 <--- (D)
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SVP
Joined: 18 Nov 2004
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One 6 = 3*25/6^3
Two 6 = 3*5/6^3
Three 6 = 1/6^3
p(e) = 91/6^3
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Director
Joined: 21 Sep 2004
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atleast.. again the way i would go is "think minus 1"
P(not getting any 6 three times would be 125/216
1-125/216= 91/216
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VP
Joined: 13 Jun 2004
Posts: 1135
Location: London, UK
Schools: Tuck'08
Followers: 5
Kudos [?]:
14
[0], given: 0
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 OA is 91/216
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