you were right the first time.

The following is the official explanation:

The total # of ways of selecting 2 persons from a set of n = nC2 = {n(n-1)}/2

The number of outcomes in which the two selected will be together = n-1.

Therefore, the # of outcomes in which they will not be together = {{n(n-1)}/2} - (n-1)

= {(n-1)(n-2)}/2.

And the probability = {(n-1)(n-2)/2}/n(n-1)/2 = 1- 2/n.

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Pls include reasoning along with all answer posts.

****GMAT Loco****

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