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# What is the probability that (u/v)/w and (x/y)/z are

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Director
Joined: 20 Jul 2004
Posts: 593
Followers: 1

Kudos [?]: 54 [0], given: 0

What is the probability that (u/v)/w and (x/y)/z are [#permalink]  26 Sep 2004, 06:58
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions
What is the probability that (u/v)/w and (x/y)/z are reciprocal fractions?

(1) v, w, y, and z are each randomly chosen from the first 100 positive integers.
(2) The product (u)(x) is the median of 100 consecutive integers.
Senior Manager
Joined: 19 May 2004
Posts: 291
Followers: 1

Kudos [?]: 9 [0], given: 0

I think it's C.

I will explain later to let other people try
Senior Manager
Joined: 19 May 2004
Posts: 291
Followers: 1

Kudos [?]: 9 [0], given: 0

Anyway, while i have the time to write:

Question:
Is (u/wv)*(x/yz)=1 ?
Or: Is u*x = y*z*w*v ?

1) Insufficient.

2) Insufficient.

What we can learn from 2 is that u*x is NOT an Integer.
That's because it's the median of an equal amount of consecutive integers.

What we learn from 1 is that y*z*w*v is an Integer.

Using both statements we know that Is u*x <> y*z*w*v.
So the probability is 0.

Director
Joined: 16 Jun 2004
Posts: 893
Followers: 2

Kudos [?]: 28 [0], given: 0

Great question. Great Answer. Brilliant one guys.

C for me too..
Director
Joined: 20 Jul 2004
Posts: 593
Followers: 1

Kudos [?]: 54 [0], given: 0

Yes, OA is C. I got this all wrong as E.
Manager
Joined: 26 Sep 2004
Posts: 137
Followers: 1

Kudos [?]: 0 [0], given: 0

Questions where statement A and statement B contradict each other thus leading to an answer have been excluded from gmat as far as i know.
Imagine choice A being that X is not negative
Choice B being that X is not positive.
The question asking for a value of X.
Can yu say that X is 0.
IF the inference was derived from another fact then a valid question but in this type NO. Be very careful that these questions r *generally* NOT going to be a past of the gmat.
_________________

Franky
http://franky4gmat.blogspot.com

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