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What is the probability that (u/v)/w and (x/y)/z are

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Director
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What is the probability that (u/v)/w and (x/y)/z are [#permalink] New post 26 Sep 2004, 06:58
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions
What is the probability that (u/v)/w and (x/y)/z are reciprocal fractions?

(1) v, w, y, and z are each randomly chosen from the first 100 positive integers.
(2) The product (u)(x) is the median of 100 consecutive integers.
Senior Manager
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 [#permalink] New post 26 Sep 2004, 07:32
I think it's C.

I will explain later to let other people try
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 [#permalink] New post 26 Sep 2004, 08:28
Anyway, while i have the time to write:

Question:
Is (u/wv)*(x/yz)=1 ?
Or: Is u*x = y*z*w*v ?

1) Insufficient.

2) Insufficient.

What we can learn from 2 is that u*x is NOT an Integer.
That's because it's the median of an equal amount of consecutive integers.

What we learn from 1 is that y*z*w*v is an Integer.

Using both statements we know that Is u*x <> y*z*w*v.
So the probability is 0.

Therefore the answer is C.
Director
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 [#permalink] New post 26 Sep 2004, 09:10
Great question. Great Answer. Brilliant one guys.

C for me too..
Director
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 [#permalink] New post 26 Sep 2004, 16:22
Yes, OA is C. I got this all wrong as E. :cry:
Manager
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 [#permalink] New post 01 Oct 2004, 21:00
Questions where statement A and statement B contradict each other thus leading to an answer have been excluded from gmat as far as i know.
Imagine choice A being that X is not negative
Choice B being that X is not positive.
The question asking for a value of X.
Can yu say that X is 0.
IF the inference was derived from another fact then a valid question but in this type NO. Be very careful that these questions r *generally* NOT going to be a past of the gmat.
_________________

Franky
http://franky4gmat.blogspot.com

  [#permalink] 01 Oct 2004, 21:00
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