if 56 is divided by 3, i get the reminder as 2, then the answer should be 2 right? how are u getting 4 as reminder and taking that as answer? request to let me know
thats because we are not asked for the remainder of 56 divided by 3. we are asked for the remainder of 2^56 divided by 7
56/3=2 indicates that is is the 2nd 'element' in the set ....
2^55 divided by 7 yields the remainder of 2;2^56 divided by 7 yields the remainder of 4;
2^57 divided by 7 yields the remainder of 1;
...which as u see from the reasoning given by brunnel....gives a remainder as 4.