Bunuel wrote:

dimitri92 wrote:

What is the Remainder R when X is divided by 8? X is a positive integer.

(1) X yields 9 when divided by 12

(2) R is a factor of 27

\(x=8q+r\), \(0\leq{r}<8\) (remainder must be less than divisor). Question \(r=?\).

(1) Think this statement should be: "x yields

remainder of 9 when divided by 12" --> \(x=12p+9\), \(x\) can take following values: 9, 21, 33, 45, 57, ... This values divided by 8 can give remainder of 1 or 5. Two values. Not sufficient.

(2) \(rk=27\), as \(0\leq{r}<8\), then r can take only two values: 1 or 3. Two values. Not sufficient.

(1)+(2) Intersection of values from (1) and (2) is \(r=1\). Sufficient.

Answer: C.

Hi Bunuel,

need ur help buddy..

Actually,when i came at the end of this problem, i had 3 and 9 as factors of 27..But,as it was given,the remainder is a factor of 27..so it only has to be 3,since 9 is greater than 8..i understand that when we divide9 by 8,we get 1 as remainder,but we are explicitly told that remainder is a factor of 27 and 1 is not a factor,so we are left with just 3..

please clear my understanding..thanks

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