bewakoof wrote:

ywilfred wrote:

(7^345 + 7^12 - 2)/7 = 7^345 + 7^12/7 - 2/7

7^345 + 7^12/7 will result in a whole number

x.000000 - 2/7 --> Remainder will be approximately 1-2/7 =0.714

I think I am gonna quote you again.. It will be 5.. think about it this way..

the first two are divisible by 7.. so remainder is gonna be 0 for themm.. right?? Now.. its like (49 +14 -2)/7 or (49 + 49 -2)/7.. No matter what remainder will always be 5..

ps: I checked it with scientific calc

I thought of it this way:

The first two are always whole numbers, I think we're on the same page on that. So it will be like:

X.00000 - 2/7 (where X is the whole number and the sting of decimal digits behind). Since 2/7 wil not have a whole number in front, to subtract we need to carry '1' from X and the string of digits at the end will look like 1-2/7 = 0.71..... which was how I got my answer.