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# What is the remainder when 9K + 1 is divided by 5?

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What is the remainder when 9K + 1 is divided by 5? [#permalink]

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15 Sep 2012, 07:14
What is the remainder when 9K + 1 is divided by 5?
(1) K = 10
(2) K = 4N + 2
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Re: What is the remainder when 9K + 1 is divided by 5? [#permalink]

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15 Sep 2012, 10:25
reks5868 wrote:
What is the remainder when 9K + 1 is divided by 5?
(1) K = 10
(2) K = 4N + 2

I would say A.

(1) K = 10 So 9K + 1 = 91. So we know remainder when 91 is divided by 5

Since Statement 1 alone is sufficient, we will check option D next (AD-BCE rule)

(2) K = 4N + 2

If N = 1, K = 6, 9K + 1 = 55 , 55/5 Remainder 0
If N = 2, K = 10, 9K + 1 = 91 , 91/5 Remainder 1
If N = 3, K = 14, 9K + 1 = 127 , 127/5 Remainder 2

So Statement 2 is not sufficient.
Re: What is the remainder when 9K + 1 is divided by 5?   [#permalink] 15 Sep 2012, 10:25
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