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What is the remainder when k^2 is divided by 8? 1). When k

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What is the remainder when k^2 is divided by 8? 1). When k [#permalink] New post 27 May 2006, 00:24
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What is the remainder when k^2 is divided by 8?
1). When k is divided by 2, the remainder is 1
2). When k is divided by 3, the remainder is 2
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Re: DS- remainder [#permalink] New post 27 May 2006, 06:23
gmat_crack wrote:
What is the remainder when k^2 is divided by 8?
1). When k is divided by 2, the remainder is 1
2). When k is divided by 3, the remainder is 2


st 1 gives allaway 1 as reminder if k^2 is divided by 8.

so A.
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Re: DS- remainder [#permalink] New post 27 May 2006, 08:43
gmat_crack wrote:
What is the remainder when k^2 is divided by 8?
1). When k is divided by 2, the remainder is 1
2). When k is divided by 3, the remainder is 2


A. stmt 1: K is odd, so the remainder is always one. Consider 9, 25, 49.
stmt 2: K could be 5, 8 and so on, the remainder is diff, so insuff.
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 [#permalink] New post 31 May 2006, 02:10
A is suff.

1) k = 2q+1
Now put values for q you will see that for every value of q, k^2/8 has remainder 1

2) k = 3y+2

Putting values different remainders come, hence not suff
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What level of difficulty do you think this is? [#permalink] New post 09 Jun 2006, 23:27
jaynayak wrote:
A is suff.

1) k = 2q+1
Now put values for q you will see that for every value of q, k^2/8 has remainder 1

2) k = 3y+2

Putting values different remainders come, hence not suff


just a thought:

I got A also. What level of difficulty do you think this is?
What level of difficulty do you think this is?   [#permalink] 09 Jun 2006, 23:27
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