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what is the remainder when n is divided by 6? 1.n divided by [#permalink ]
05 Sep 2007, 05:47

what is the remainder when n is divided by 6?
1.n divided by 4 gives remainder 3.
2.n divided by 3 gives remainder 5.
I know some might say stmt 2 is not correct..It is indeed correct.
Please explain

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Re: what is the remainder when n is divided by 6? [#permalink ]
05 Sep 2007, 05:55

humtum0 wrote:

what is the remainder when n is divided by 6? 1.n divided by 4 gives remainder 3. 2.n divided by 3 gives remainder 5. I know some might say stmt 2 is not correct..It is indeed correct. Please explain

Tried out a few numbers and got C.

(1) if n=7, n/6 has remainder of 1

if n=11, n/6 has remainder of 5

INSUFFICIENT

(2) if n=8, n/6 has remainder of 2

if n=11, n/6 has remainder of 5

INSUFFICIENT

Together, the numbers that works are 11, 23, 35, and n/6 always has remainder of 5

SUFFICIENT.

Last edited by

bkk145 on 05 Sep 2007, 06:49, edited 2 times in total.

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Re: what is the remainder when n is divided by 6? [#permalink ]
05 Sep 2007, 06:46

bkk145 wrote:

humtum0 wrote:

what is the remainder when n is divided by 6? 1.n divided by 4 gives remainder 3. 2.n divided by 3 gives remainder 5. I know some might say stmt 2 is not correct..It is indeed correct. Please explain

Tried out a few numbers and got C.

(1) if n=7, n/6 has remainder of 1

if n=11, n/6 has remainder of 5

INSUFFICIENT

(2) if n=8, n/6 has remainder of 2

if n=11, n/6 has remainder of 5

INSUFFICIENT

Together, the numbers that works are 11, 23, 25, and n/6 always has remainder of 3

SUFFICIENT.

if u calculate prop 11/6 gives remainder of 5, 25/6 gives 1..

n moreover 25 shud give remainder of 3 wen divided by 4

i think ans is E

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Re: what is the remainder when n is divided by 6? [#permalink ]
05 Sep 2007, 06:48

12345678 wrote:

bkk145 wrote:

humtum0 wrote:

what is the remainder when n is divided by 6? 1.n divided by 4 gives remainder 3. 2.n divided by 3 gives remainder 5. I know some might say stmt 2 is not correct..It is indeed correct. Please explain

Tried out a few numbers and got C.

(1) if n=7, n/6 has remainder of 1

if n=11, n/6 has remainder of 5

INSUFFICIENT

(2) if n=8, n/6 has remainder of 2

if n=11, n/6 has remainder of 5

INSUFFICIENT

Together, the numbers that works are 11, 23, 25, and n/6 always has remainder of 3

SUFFICIENT.

if u calculate prop 11/6 gives remainder of 5, 25/6 gives 1..

n moreover 25 shud give remainder of 3 wen divided by 4

i think ans is E

Opps, sorry, it should be 5, not 3. and 35, not 25...I edited my post.

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I get C too...
here is how I would do it..
from 1) N=4K+3 i.e 7, 11 15, 19, 23, 27
from 2) N=3K+5 i.e 8, 11, 14, 17, 23, 26,
you will notice that the numbers 11, 23 are common between the 2 statements..go ahead and try you will see that every 12 numbers apart you will have a number that satisfies both statement 1 and 2...
11/6 or 23/6 give remainder 5...
C it is..

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each separately is not enough
it can be checked whether together they are sufficient:
4x+3 = n
when x = 1 2 3 4 5 6 7 8...
than remainder = 1 5 3 1 5 3 1 5 ... (1 5 3 repeats)
3x+5 = n
when y = 1 2 3 4 5 6 7 8 ...
then n = 2 5 2 5 2 5 2 5 ... (2 5 repeats)
there are some numbers as 2, 8, 14, 20 ... in which remainder is the same for both equations (these numbers are just plug ins) only these so called 'plug ins' satisfy both equations at the same time.
So the answer is C

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Thanks Guys
OA is 'C'

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Re: what is the remainder when n is divided by 6? [#permalink ]
05 Sep 2007, 20:40

humtum0 wrote:

what is the remainder when n is divided by 6? 1.n divided by 4 gives remainder 3. 2.n divided by 3 gives remainder 5. I know some might say stmt 2 is not correct..It is indeed correct. Please explain

Im confused. I cant find any numbers that leave a remainder of 5 when divided by 3...

S1 insuff.

S2: can't find anything by 3 that leaves a remainder of 5. lil help guys

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Re: what is the remainder when n is divided by 6? [#permalink ]
06 Sep 2007, 16:53

GMATBLACKBELT wrote:

Im confused. I cant find any numbers that leave a remainder of 5 when divided by 3...

S1 insuff.

S2: can't find anything by 3 that leaves a remainder of 5. lil help guys

ST 2

n=3T+5

(3*1+5)/6= rem 2

(3*2+5)/6= rem 5

(3*3+5)/6= rem 2

(3*4+5)/6= rem 5

.....

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St1
n = 4q1 + 3
If q1 = 1, then n = 7 and n/6 gives remaider of 1.
If q1 = 2, then n = 11 and n/6 gives remainder of 5.
Insufficient.
St2:
n = 3q2 + 5
If q2 = 1, then n = 8 and n/6 gives remainder of 2.
If q2 = 2, then n = 11 and n/7 gives remainder of 5.
Insufficient.
Using both St1 and st2:
From 1, n could be 7,11,15,19,23,27,31....
From 2, n could be 8,11,14,17,20,23,26,29,32....
n = 11 -> n/6 --> remainder of 5
n = 23 -> n/6 --> remainder of 5
Should result in remainder of 5. Sufficient.
Ans C

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