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What is the remainder when the positive integer n is divided

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Senior Manager
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What is the remainder when the positive integer n is divided [#permalink] New post 18 Jan 2006, 18:58
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A
B
C
D
E

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100% (01:28) correct 0% (00:00) wrong based on 3 sessions
What is the remainder when the positive integer n is divided by 2?
(1) When n is divided by 5, the remainder is an odd integer.
(2) When n is divided by 10, the remainder is an odd integer.
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 [#permalink] New post 18 Jan 2006, 20:25
D.
1) the remainder is 0

2) the remaider is 1
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 [#permalink] New post 18 Jan 2006, 20:41
I`d say (C).

The number "13" illustrates this just fine.
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Re: DS remainder..simple [#permalink] New post 18 Jan 2006, 21:17
sperumba wrote:
What is the remainder when the positive integer n is divided by 2?
(1) When n is divided by 5, the remainder is an odd integer.
(2) When n is divided by 10, the remainder is an odd integer.


B is enough. no matter what is the value of the odd interger, the reminder is 1 when this odd integer is divided by 2.
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Re: DS remainder..simple [#permalink] New post 18 Jan 2006, 22:36
sperumba wrote:
What is the remainder when the positive integer n is divided by 2?
(1) When n is divided by 5, the remainder is an odd integer.
(2) When n is divided by 10, the remainder is an odd integer.


Question is n even!

n/5 remainder is odd => n = a*5 + b for a=odd n is even for a=even n is odd or in other ex...for 8 and 13 both remainder is odd
so insuff
n/10 remainder is odd => n = a*10 + b, b is odd, a*10 is even so a*10+b is odd so n is not even! Suff.
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 [#permalink] New post 19 Jan 2006, 02:29
B

St1: n = 5*a + Odd, where a is a positive integer.

a can be even or odd.

If a is even then n is odd and remainder will be 1 , if divided by 2.
If a is odd then n is even and remainder will be 0 , if divided by 2.

So INSUFF

St2: n = 10*a + Odd, where a is a positive integer.

Whatever is the value of a (Either even or odd), n will be always odd. So n divided by 2 will yield a remainder of 1. So SUFF
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 [#permalink] New post 21 Jan 2006, 20:43
B for me
Q=Quotitent R=Remainder

a)5Q+R=N R ={1,3,5,7,9}

Lets do for Q=1 and Q=2
N=5*1+1=6 (when divided by 2, the remainder would be 0)
N=5*2+1=11 (when divided by 2, remainder would be 1)
So insuff

b)10Q+R=N R=(1,2,,5,7}
Any multiple of 10 would be even and even+odd=odd
Any odd number divided by 2 would give 1 as remainder
So B
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 [#permalink] New post 21 Jan 2006, 22:24
celiaXDN wrote:
D.
1) the remainder is 0

2) the remaider is 1


Got B as well.

Consider 11 in first case to break the argument.
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Re: DS remainder..simple [#permalink] New post 31 Jan 2006, 20:36
sperumba wrote:
What is the remainder when the positive integer n is divided by 2?
(1) When n is divided by 5, the remainder is an odd integer.
(2) When n is divided by 10, the remainder is an odd integer.


Why isn't the answer D? Either choice gives you a remainder of 1 when you divide the remainders in (1) and (2) by 2.
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 [#permalink] New post 01 Feb 2006, 00:47
B.

Stat 2 is sufficient to answer the question

Let say n= 11,13,15,17,19,21 and son on

remainder is always 1 when divided by 2


Stat 1 is not sufficient,

lets say n= 6,8,11,13,16,18 and so on

remainder is 0 or 1 when divided by 2,.
  [#permalink] 01 Feb 2006, 00:47
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