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What is the remainder when the positive integer x is divided

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Senior Manager
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What is the remainder when the positive integer x is divided [#permalink] New post 11 Nov 2007, 12:12
What is the remainder when the positive integer x is divided by 8?

(1) When x is divided by 12, the remainder is 5.

(2) When x is divided by 18, the remainder is 11.
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Re: Data sufficiency - remainder [#permalink] New post 11 Nov 2007, 13:06
gluon wrote:
What is the remainder when the positive integer x is divided by 8?

(1) When x is divided by 12, the remainder is 5.

(2) When x is divided by 18, the remainder is 11.


1. x/12 remainder is 5. then x=17, 29, 41 not suff.

2. x/18 remainder is 11, then x=29, 47, 55 not suff.

combined x=29
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Re: Data sufficiency - remainder [#permalink] New post 11 Nov 2007, 13:29
gluon wrote:
What is the remainder when the positive integer x is divided by 8?

(1) When x is divided by 12, the remainder is 5.

(2) When x is divided by 18, the remainder is 11.


i get E

8x + R, what is R?

1) 12k + 5
5, 17, 29, 41, 53, 65, 77, 89
remainder of 8x could be 1,3, or 5

2) 18k + 11
11, 29, 47, 65, 83, 101
remainder of 8x could be 1,3,5,6

combining 1) and 2)
29, 65
remainder could be 1 or 5
not sufficient

Last edited by beckee529 on 11 Nov 2007, 14:04, edited 1 time in total.
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 [#permalink] New post 11 Nov 2007, 13:54
I'm prob way off with this but whatever...


x=12q +5

x=18q +11

Solve...12q + 5 = 18q + 11

q = -1

so..

x = -7

So -7/8 has no remainder. Answer C.
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 [#permalink] New post 11 Nov 2007, 14:03
fresinha12 wrote:
looks to be C...


its E..
x can be 29, 65...

the remainder can be 5 or 1..
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 [#permalink] New post 11 Nov 2007, 14:12
Can anyone show how to solve with the reminder formula or something more robust than trial and error?
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Re: Data sufficiency - remainder [#permalink] New post 12 Nov 2007, 03:15
gluon wrote:
What is the remainder when the positive integer x is divided by 8?

(1) When x is divided by 12, the remainder is 5.

(2) When x is divided by 18, the remainder is 11.


Getting E.

Stat 1: x = 65 r = 1, x = 5 r = 5. Insuff.

Stat 2: x = 29 r= 5, x = 47 r = 1. Insuff.

Stat 1 & 2: x = 29 r = 5, x = 65 r = 1. Insuff.
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 [#permalink] New post 12 Nov 2007, 09:05
jimmyjamesdonkey wrote:
Can anyone show how to solve with the reminder formula or something more robust than trial and error?


Is there a more methodical way or are remainder problems trial and error? :?:
  [#permalink] 12 Nov 2007, 09:05
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