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What is the remainder when the positive integer x is divided

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VP
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What is the remainder when the positive integer x is divided [#permalink] New post 26 Dec 2007, 08:31
What is the remainder when the positive integer x is divided by 6?

1. when x is divided by 2, the remainder is 1; and wheen x is divided by 3, the remainder is 0
2. when x is divided by 12, the remainder is 3
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 [#permalink] New post 26 Dec 2007, 09:46
1. X is a multiple of 3 (3, 6, 9, 12, 15, etc) insufficient
2. X is 15+12y (15, 27, 39, 51, 63 etc) SUFFICIENT remainder is always 3

answer is B
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Re: remainder [#permalink] New post 26 Dec 2007, 09:54
marcodonzelli wrote:
What is the remainder when the positive integer x is divided by 6?

1. when x is divided by 2, the remainder is 1; and wheen x is divided by 3, the remainder is 0
2. when x is divided by 12, the remainder is 3


1. X is multiple of 3 AND odd - remainder is always 3 (9,15,21) Suff
2. X=15+12y=3+12(1+y) - remainder is always 3 Suff

Answer D
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 [#permalink] New post 26 Dec 2007, 09:56
eschn3am wrote:
1. X is a multiple of 3 (3, 6, 9, 12, 15, etc) insufficient
2. X is 15+12y (15, 27, 39, 51, 63 etc) SUFFICIENT remainder is always 3

answer is B


i believe that the answer is (E).
x could be all of those numbers that uve mentioned but we still need to find x to determine the remainder when, x is divided by 6, which is not sufficiently answered neither by 1 nor 2.

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 [#permalink] New post 26 Dec 2007, 10:03
OA is D guys...explanations???
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Re: remainder [#permalink] New post 26 Dec 2007, 10:05
cstefanita wrote:
marcodonzelli wrote:
What is the remainder when the positive integer x is divided by 6?

1. when x is divided by 2, the remainder is 1; and wheen x is divided by 3, the remainder is 0
2. when x is divided by 12, the remainder is 3


1. X is multiple of 3 AND odd - remainder is always 3 (9,15,21) Suff
2. X=15+12y=3+12(1+y) - remainder is always 3 Suff

Answer D


aah, forgot about the first part of 1. answer is definitely D.

and we don't need to know EXACTLY what number X is because the remainder when divided by 6 is always 3. that's all we need to know.
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Re: remainder [#permalink] New post 26 Dec 2007, 10:57
Look at this....

from 1. we know that: x/2=q + 1/2, where q is the quotient and 1 the remainder. we also know that x/3=q, so lt's substitute and obtain 3/6*x=2/6*x + 3/6...3 is the remainder

from 2. x/12=q + 3/12..let's multiply by 2: 2x/6=q + 3/6.....the remainder is 3

is that crazy???
Re: remainder   [#permalink] 26 Dec 2007, 10:57
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