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1. X is a multiple of 3 (3, 6, 9, 12, 15, etc) insufficient 2. X is 15+12y (15, 27, 39, 51, 63 etc) SUFFICIENT remainder is always 3

answer is B

i believe that the answer is (E).
x could be all of those numbers that uve mentioned but we still need to find x to determine the remainder when, x is divided by 6, which is not sufficiently answered neither by 1 nor 2.

from 1. we know that: x/2=q + 1/2, where q is the quotient and 1 the remainder. we also know that x/3=q, so lt's substitute and obtain 3/6*x=2/6*x + 3/6...3 is the remainder

from 2. x/12=q + 3/12..let's multiply by 2: 2x/6=q + 3/6.....the remainder is 3

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