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What is the remainder when X, an integer, is divided by 88

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What is the remainder when X, an integer, is divided by 88 [#permalink] New post 01 Apr 2004, 00:52
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What is the remainder when X, an integer, is divided by 88

(1) X when divided by 11 leaves remainder 3
(2) 3X when divided by 24 leaves remainder 12
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 [#permalink] New post 01 Apr 2004, 07:25
C it is..........88 can be factored into 11 & 8.stem one the divisor is 11 and stem 2 the divisor is 3X/24 or X/8....hence sufficient!!
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 [#permalink] New post 06 Apr 2004, 16:43
I used trial and error to arrive at the answer. Please show your method if you have better one.
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 [#permalink] New post 22 May 2004, 06:34
Ans is C.

Kind of series it is.

from 1, 11a + 3 = x
from 2, 8b + 4 = x

implies, 11a = 8b + 1

Pairs: (a, b) = (11, 15), (19, 26), (27, 37) ..............
x = 121, 209, 297 ..............

In all the above cases remainder is 33.

cheers
  [#permalink] 22 May 2004, 06:34
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What is the remainder when X, an integer, is divided by 88

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