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What is the square root of 3^(6x-4)

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What is the square root of 3^(6x-4) [#permalink] New post 14 Apr 2006, 17:07
What is the square root of 3^(6x-4)?
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 [#permalink] New post 14 Apr 2006, 17:12
Wild guess, but

3^(3x-2)?
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 [#permalink] New post 14 Apr 2006, 20:03
sqrt(3^(6x-4)) = ( 3^(6x-4) )^1/2 = 3^(3x-2).

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Re: square rts [#permalink] New post 14 Apr 2006, 20:49
joemama142000 wrote:
What is the square root of 3^(6x-4)?

= square root of 3^(6x-4)
= [3^(6x-4)]^1/2
= 3^{(6x/2)-(4/2)}
= 3^{(3x)-(2)}
= 3^(3x-2)
Re: square rts   [#permalink] 14 Apr 2006, 20:49
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What is the square root of 3^(6x-4)

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