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What is the sum of the integers A and B? 1. A=-/B/ 2.B=-/A

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What is the sum of the integers A and B? 1. A=-/B/ 2.B=-/A [#permalink]

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21 Jan 2006, 21:52
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What is the sum of the integers A and B?

1. A=-/B/
2.B=-/A/
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21 Jan 2006, 22:14
Thinking E here.

1) With some examples I found tha A = -|B|
=> A = B or A = -B or A = B = 0
2) Same as 1) B = -A or B =A or A = B = 0.

So in my opinion 1) & 2) are the same. Hence E.
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Re: DS (Sum of intergers) [#permalink]

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21 Jan 2006, 22:26
rlevochkin wrote:
What is the sum of the integers A and B?

1. A=-/B/
2.B=-/A/

from i, A=-/B/, suppose b=1
A=-/1/=-1, a+b=1-1=0
suppose b=-1
A=-/-1/=-1, a+b=-1-1=-2
suppose b=0
A=-/0/=0, a+b=0+0=0

from ii, B=-/A/. it is also the same as i.
ok, agree with E.
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22 Jan 2006, 00:54
D it is

St1: This is possible only when A = 0 and B = 0 So Sum = 0

St2: This is possible only when A = 0 and B = 0 So Sum = 0
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22 Jan 2006, 02:27
think it should be C)
stmnt 1) B=5 A=-5 sum is 0
B=-5 A=-5 sum is -10

Stmnt 2) A=5 B=-5 sum is 0
A=-5 B=-5 sum is -10

combining both gives A=-5 B=-5
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Re: DS (Sum of intergers) [#permalink]

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22 Jan 2006, 04:43
Professor wrote:
rlevochkin wrote:
What is the sum of the integers A and B?

1. A=-/B/
2.B=-/A/

from i, A=-/B/, suppose b=1
A=-/1/=-1, a+b=1-1=0
suppose b=-1
A=-/-1/=-1, a+b=-1-1=-2
suppose b=0
A=-/0/=0, a+b=0+0=0

from ii, B=-/A/. it is also the same as i.
ok, agree with E.

Agree with your approach, it's E
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Re: DS (Sum of intergers) [#permalink]

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22 Jan 2006, 09:33
rlevochkin wrote:
What is the sum of the integers A and B?

1. A=-/B/
2.B=-/A/

OK lets see....

(1) pick number b=1

then a=-1, then a+b=-1+1=0

say b=-1

then a=-1, -1-1=-2..Insuff

(2) same approach as above

together insuff

E it is...
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22 Jan 2006, 21:11
Go with E.

1. A = -1, B can be 1,-1. A+B = 0 or -2.
2. Same as above.

Combining, I can't figure out additional info.
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Re: DS (Sum of intergers) [#permalink]

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05 Jun 2007, 16:17
rlevochkin wrote:
What is the sum of the integers A and B?

1. A=-/B/
2.B=-/A/

if A = -B, and B = - A, then A +B = 0.

but

A = - /B/ is not the same as A = -B. similarly B = -/A/ is also different from B = -A.

So E, not D, should be the answer.
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06 Jun 2007, 22:35
(1)
1) a=-b ---> a+b = 0
2) a=b ----> a+b =2b
(2)
1) b=a ----> a+b=2a
2) b=-a ---> a+b=0

What is OA?
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06 Jun 2007, 23:07
I'm getting E too.

S1. A = -|B|
B=1
A= -1
A+B=0
B=-1
A=-1
A+B=-2

S2. B= -|A|
Alone, we have the same reasons as above

S1&S2.
From S1 we have if B=-1, A=-1
Put A=-1 in S2 we get B=-1

Both the equations are satisfied here. But this applies to all negative numbers.

So A+B = Unknown
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06 Jun 2007, 23:17
From 1) A=-/B/ which means that a) A=B or b)A = -B
from a) A-B=0, from b) A+B=0, adding both equations, 2A=0 so A=0, subtracting both equations gives B=0 so A+B=0. So sufficeint. Similarly statement 2 is also sufficient. So it has to be D. Only 0 suffices the conditions.
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07 Jun 2007, 10:48
(E)

(1) --------INSUFFF

&

(2) --------INSUFFF

TOGETHER (1) + (2) =>

A+B = -{ l A l + l B l } gives diff. values. for diff values of A & B.INSUFF.
07 Jun 2007, 10:48
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What is the sum of the integers A and B? 1. A=-/B/ 2.B=-/A

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