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What is the sum of the square of the first n positive

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Manager
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What is the sum of the square of the first n positive [#permalink] New post 26 Jan 2005, 22:11
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What is the sum of the square of the first n positive integer if the sum of the square of the first n even positive integer is A

1. 3A/4
2. A/2
3. A/3
4. A/4
5. A/8
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 [#permalink] New post 26 Jan 2005, 22:17
A=2^2+4^2+6^2+...=2^2*1^2+2^2*2^2+2^2*3^2+...=2^2(1^2+2^2+3^2+...)=4S

S=A/4
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 [#permalink] New post 26 Jan 2005, 23:07
praveen_rao7 wrote:
shouldn't the answer be > A?


Nope.............

suppose n = 4

sum of sq of first n +ve even integers(A)= 2^2+4^2+6^2+8^2=120
sumof sq of first n +ve integers (a) =1^2+2^2+3^4^2 = 30
A/a=120/30
a=A/4
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 [#permalink] New post 31 Jan 2005, 03:57
Great explanation. Just need to get used to the symbols here which tend to make things a little more confusing. Once I re-wrote using normal notation it made much more sense.
  [#permalink] 31 Jan 2005, 03:57
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