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Re: tens' digit [#permalink]
LM wrote:
What is the tens' digit of the sum of the first 40 terms of 1,11,111,1111,11111,111111,.......?

A)2
B)3
C)4
D)8
E)9


All of the first 40 terms have 1 at the units place.
Except the first term, the tens digit of all the remaining 39 terms is 1.

So now if you do the addition

1 1
1 1
. . .
. . .
. . .
1 1
0 1
3 0

Answer is B
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Re: What is the tens' digit of the sum of the first 40 terms of [#permalink]
LM wrote:
What is the tens' digit of the sum of the first 40 terms of 1, 11, 111, 1111, 11111, 111111, ...?

A. 2
B. 3
C. 4
D. 8
E. 9


40*1 (units digits) = 40, carry over 4
39*1 + 4 = 43, carry over 4

Answer: B
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Re: What is the tens' digit of the sum of the first 40 terms of [#permalink]
LM wrote:
What is the tens' digit of the sum of the first 40 terms of 1, 11, 111, 1111, 11111, 111111, ...?

A. 2
B. 3
C. 4
D. 8
E. 9


:( I misunderstood when reading the problem. Tens's digit = tenth digit :( OMG
Anyways, the answer should be B
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Re: What is the tens' digit of the sum of the first 40 terms of [#permalink]
What is the tens' digit of the sum of the first 40 terms of 1, 11, 111, 1111, 11111, 111111, ...?

A. 2
B. 3
C. 4
D. 8
E. 9
______________________________

1
+ 11
+111
.
.
40 terms
That means for unit digit there are 40 1s hence unit digit will be 0 and carry over is 4

Now while adding the second term there are only 39 terms ( as we have used up 1st term which was "1"
Now 39 + 4 = 43

Hence tens' digit is 3

Posted from my mobile device
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Re: What is the tens' digit of the sum of the first 40 terms of [#permalink]
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Re: What is the tens' digit of the sum of the first 40 terms of [#permalink]
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