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Thanks brstorewala for sharing this interesting math DS problem.
I wonder where are the source to get all these questions?

I already studied the Kaplan book, but wasn't feeling it too helpful.
I got most questions right in practice but I didn't do that well in real GMAT test with the time concern. Any suggestion?

With almost two minutes for each question on the math section and around 110 sec for each question on the verbal section, time does not seem to be a major concern. The problem is that the mind goes blank. I experienced it when I took my PP test at home. Especially for the RC part, I was not able to think clearly. It was like my mind was clouded and I was blank. So it is really a matter of how calm and composed you are, assuming that you have practiced sufficiently. I am a proponent of the philosophy of "practice as much as u can"......2k, 5k, 10k......any number of questions....the key is getting a feel, making sure that you don't see a different "kind" of a problem in the exam. Of course strategy is important, so I make this summary kind of a thing for each section, in which i note down the main testing points and rules. The summary would be very handy toward the end of your preparation schedule. Those are my two cents.....i am just waiting to see how my philosophy and strategy work on the "D" day.........it all boils down to those 4 bloody hours.......

With almost two minutes for each question on the math section and around 110 sec for each question on the verbal section, time does not seem to be a major concern. The problem is that the mind goes blank. I experienced it when I took my PP test at home. Especially for the RC part, I was not able to think clearly. It was like my mind was clouded and I was blank. So it is really a matter of how calm and composed you are, assuming that you have practiced sufficiently. I am a proponent of the philosophy of "practice as much as u can"......2k, 5k, 10k......any number of questions....the key is getting a feel, making sure that you don't see a different "kind" of a problem in the exam. Of course strategy is important, so I make this summary kind of a thing for each section, in which i note down the main testing points and rules. The summary would be very handy toward the end of your preparation schedule. Those are my two cents.....i am just waiting to see how my philosophy and strategy work on the "D" day.........it all boils down to those 4 bloody hours.......

Cool... A sort of philosophy... Brstorewala, have you ever tried to write a philosophic treatise? You are to be successful. No doubt.

A ) Using the average, find the midpoint of series. It will be 45th term with values of 89*100/89 = 100. To get 10th term, there are 35 jumps of 1 point worth each. Hence 10th term = 100 - 35 * 1= 65.

A is sufficient.

B) Similarly here 79th term is 134. To reach 10th term, there are 69 jumps worth 1 point each. Hence 10th term = 134 - 69 = 65.

Re: What is the tenth term in a series of 89 consecutive [#permalink]

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25 Sep 2015, 13:35

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Re: What is the tenth term in a series of 89 consecutive [#permalink]

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24 Dec 2015, 07:32

Consecutive integers means they are all distinct and are in AP.

In an AP with odd number of term the median and the mean are the same.

Statement 1: 100 is the mean and also the median. So 100 is the 45th terms. We just subtract 44 and get the answer. Also, it works becasue they are consecutive integer. Had it been an AP of non consecutive integers, this wouldn't have worked

Anyways, the statement is sufficient

Statement 2: Gives one of the terms The common difference is 1 (consecutive integers)

Sufficient to back track or use AP formulas to find any other term in the series.

Hence Each statement alone is sufficient. D _________________

What is the tenth term in a series of 89 consecutive [#permalink]

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16 Jul 2016, 02:20

brstorewala wrote:

What is the tenth term in a series of 89 consecutive positive integers?

(1) The average of the integers is 100 (2) The 79th term in the series is 134

(1) The average of the integers is 100 Sufficient (first+last term)/2=100 first + last =200 since there are total of 89 numbers and all numbers are consecutive; therefore last term = first+88 First+(First+88)=200 2*first=112 FIRST TERM=56 the first term is 56 therefore the tenth term will be 65 SUFFICIENT

(2) The 79th term in the series is 134 SUFFICIENT:- 79 term is 134, so we can reverse count the 10th term or (79th-69th) term = (134-69) or 10th term =65

BOTH STATEMENT GIVES US ANSWER

SO D IS THE ANSWER _________________

Posting an answer without an explanation is "GOD COMPLEX". The world does't need any more gods. Please explain you answers properly.

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