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(2) t - x = 5 --> \(\frac{2t + (t - x)}{(t - x)}=\frac{2t + 5}{5}\) --> different values of t will give different values ofr this expression. Not sufficient.

Re: What is the value of (2t + t - x)/(t - x)? [#permalink]

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19 Aug 2014, 19:30

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Re: What is the value of (2t + t - x)/(t - x)? [#permalink]

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04 Feb 2016, 22:30

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Re: What is the value of (2t + t - x)/(t - x)? [#permalink]

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06 Feb 2016, 12:56

Walkabout wrote:

What is the value of (2t + t - x)/(t - x)?

(1) 2t/(t - x) = 3

(2) t - x = 5

Statement 1. Multiply both sides by (t-x) ==> 2t=3t-3x Hence t=3x Plug in original equation to get (6x+9x-x)/2x = 7 Statement 2. x=t-5 Plug in original expression to get (2t-5)/5 Clearly not sufficient _________________

hi, you are to find the value of an equation which consists of two variables... when nothing is given, you cannot assume one value to be some integer and work for second... If there was a statement given that t=3, what would you do then.. someone can take values of both t and x and will not require any statement.. The main point is that you cannot do it this way.. _________________

This is the beauty of DS questions. You are assuming the very thing that you need to show is sufficient. To evaluate options in a DS question, you need to be absolutely sure that you get a unique value for the question asked. In this case, statement 1 clearly is sufficient as you can see in the solutions posted above.

Question for you. How do you know that 't' is the ONLY variable ? I can assume both t and x to be constants while at the same time someone else can assume both of these or one of these to be constants. This is the very reason why you can not assume values in a DS question if it is not mentioned clearly in the question or the given statements.

FYI, t=5 and x=2 also satisfy the given conditions.

Your approach might have worked in a PS question but do not adopt this strategy for DS questions. _________________

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