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What is the value of 3^-(x + y) / 3^-(x - y)? (1) x = 2 (2)

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What is the value of 3^-(x + y) / 3^-(x - y)? (1) x = 2 (2) [#permalink] New post 05 May 2006, 19:51
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What is the value of 3^-(x + y) / 3^-(x - y)?
(1) x = 2
(2) y = 3
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Re: DS: value of 3^-(x+y). [#permalink] New post 05 May 2006, 20:49
M8 wrote:
What is the value of 3^-(x + y) / 3^-(x - y)?
(1) x = 2
(2) y = 3


= 3^-(x + y) / 3^-(x - y)
= 3^(x - y)/3^(x + y)
= 3^x 3^-y/3^x 3^y
= 1/ 3^2y

so 2 is suff. B.
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 [#permalink] New post 05 May 2006, 20:56
A for me
3^-(x + y) / 3^-(x - y)={1/3^(x+y)}/{1/3^(x-y)}
=3^(x-y)/3^(x+y)=3^(x+y)*3^(x-y)=3^x+y+x-y=3^2x=3^4
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 [#permalink] New post 06 May 2006, 09:07
Anybody else? :wink:
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 [#permalink] New post 06 May 2006, 09:58
I agree with B :wink:
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 [#permalink] New post 06 May 2006, 10:07
Yurik79 wrote:
A for me
3^-(x + y) / 3^-(x - y)={1/3^(x+y)}/{1/3^(x-y)}
=3^(x-y)/3^(x+y)=3^(x+y)*3^(x-y)=3^x+y+x-y=3^2x=3^4


The calculation done by you here is wrong. The X part gets cancelled rather than the Y. Hence 2nd stmt is sufficient.
So Answer is B
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 [#permalink] New post 06 May 2006, 10:16
3^-(x + y) / 3^-(x - y)={1/3^(x+y)}/{1/3^(x-y)}
=3^(x-y)/3^(x+y)=3^(x+y)*3^-(x+y)
My fault))stupid mistake[/b]
Agree B it is
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 [#permalink] New post 06 May 2006, 15:12
Agreed with B,,, Made stupid mistakes!
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 [#permalink] New post 06 May 2006, 15:22
Yes, it depends on the value of y. Answer is B.
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 [#permalink] New post 10 May 2006, 19:22
3^-(x + y) / 3^-(x - y)
= 1/3^(x+y) x 3^(x-y)
= 3^(x-y)/3^(x+y)
= 3^x(3^-y)/3^x(3^y)
= 1/3^2y

St1:
Insufficient.

St2:
Sufficient.

Ans B
  [#permalink] 10 May 2006, 19:22
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