What is the value of 3^-(x + y) / 3^-(x - y)? (1) x = 2 (2)

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What is the value of 3^-(x + y) / 3^-(x - y)? (1) x = 2 (2) [#permalink]

05 May 2006, 20:51

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What is the value of 3^-(x + y) / 3^-(x - y)?
(1) x = 2
(2) y = 3

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Re: DS: value of 3^-(x+y). [#permalink]

05 May 2006, 21:49

M8 wrote:

What is the value of 3^-(x + y) / 3^-(x - y)?
(1) x = 2
(2) y = 3

= 3^-(x + y) / 3^-(x - y)
= 3^(x - y)/3^(x + y)
= 3^x 3^-y/3^x 3^y
= 1/ 3^2y

so 2 is suff. B.

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05 May 2006, 21:56

A for me
3^-(x + y) / 3^-(x - y)={1/3^(x+y)}/{1/3^(x-y)}
=3^(x-y)/3^(x+y)=3^(x+y)*3^(x-y)=3^x+y+x-y=3^2x=3^4
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06 May 2006, 10:07

Anybody else? :wink:

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06 May 2006, 10:58

I agree with B :wink:

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06 May 2006, 11:07

Yurik79 wrote:

A for me
3^-(x + y) / 3^-(x - y)={1/3^(x+y)}/{1/3^(x-y)}
=3^(x-y)/3^(x+y)=3^(x+y)*3^(x-y)=3^x+y+x-y=3^2x=3^4

The calculation done by you here is wrong. The X part gets cancelled rather than the Y. Hence 2nd stmt is sufficient.
So Answer is B

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06 May 2006, 11:16

3^-(x + y) / 3^-(x - y)={1/3^(x+y)}/{1/3^(x-y)}
=3^(x-y)/3^(x+y)=3^(x+y)*3^-(x+y)
My fault))stupid mistake[/b]
Agree B it is
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06 May 2006, 16:12

Agreed with B,,, Made stupid mistakes!

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06 May 2006, 16:22

Yes, it depends on the value of y. Answer is B.
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10 May 2006, 20:22

3^-(x + y) / 3^-(x - y)
= 1/3^(x+y) x 3^(x-y)
= 3^(x-y)/3^(x+y)
= 3^x(3^-y)/3^x(3^y)
= 1/3^2y

St1:
Insufficient.

St2:
Sufficient.

Ans B

[#permalink] 10 May 2006, 20:22

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What is the value of 3^-(x + y) / 3^-(x - y)? (1) x = 2 (2)

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What is the value of 3^-(x + y) / 3^-(x - y)? (1) x = 2 (2)

What is the value of 3^-(x + y) / 3^-(x - y)? (1) x = 2 (2)

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