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For (1), pick some numbers. A = 7, B = 3, C = 4, D = 6 → C + B = 7 A = 1, B = 9, C = 3, D = 7 → C + B = 12 No single value Insufficient.
For (2), It does not even contain the variable C. Insufficient. Combined: Notice in this problem that there are several sets of 2 variable terms and they're all equal. From (2), (D – B) = (E + F) → C + D = D–B. Add B to both sides and subtract D from both sides → C + B = 0. Sufficient.
Hi, I want to know if we can solve Statement (1) without pick number, please. I think it does not have C + B in equation, it is insufficient.
Re: What is the value of C + B? (1) A + B = C + D = E + F [#permalink]
05 Feb 2014, 16:20
1
This post received KUDOS
Let me try,
We can rearrange the equations:
C = E+F - D B = E+F - A
All 3 equalities given would boil down to this,
C+B = 2 (E+F) - (A+D)
So C+B depends on 4 different variables which are still unknown. In other words there are infinitely many number of possibilities for C+B when the Statement 1 alone is considered.
For (1), pick some numbers. A = 7, B = 3, C = 4, D = 6 → C + B = 7 A = 1, B = 9, C = 3, D = 7 → C + B = 12 No single value Insufficient.
For (2), It does not even contain the variable C. Insufficient. Combined: Notice in this problem that there are several sets of 2 variable terms and they're all equal. From (2), (D – B) = (E + F) → C + D = D–B. Add B to both sides and subtract D from both sides → C + B = 0. Sufficient.
Hi, I want to know if we can solve Statement (1) without pick number, please. I think it does not have C + B in equation, it is insufficient.
You don't really need to do anything in statement (1)
(1) A + B = C + D = E + F Each equation you can make has 4 different variables in it. We don't have the value of any variable. Hence, there is no way you can find the value of B+C. B and C could innumerable values and their sum could be anything.
Using both statements together, A + B = C + D = E + F (E + F) = (D – B), focus on B and C and eliminate as many variables as you can
For (1), pick some numbers. A = 7, B = 3, C = 4, D = 6 → C + B = 7 A = 1, B = 9, C = 3, D = 7 → C + B = 12 No single value Insufficient.
For (2), It does not even contain the variable C. Insufficient. Combined: Notice in this problem that there are several sets of 2 variable terms and they're all equal. From (2), (D – B) = (E + F) → C + D = D–B. Add B to both sides and subtract D from both sides → C + B = 0. Sufficient.
Hi, I want to know if we can solve Statement (1) without pick number, please. I think it does not have C + B in equation, it is insufficient.
You don't really need to do anything in statement (1)
(1) A + B = C + D = E + F Each equation you can make has 4 different variables in it. We don't have the value of any variable. Hence, there is no way you can find the value of B+C. B and C could innumerable values and their sum could be anything.
Using both statements together, A + B = C + D = E + F (E + F) = (D – B), focus on B and C and eliminate as many variables as you can
you get C + D = D - B B + C = 0
Answer (C)
Statement 1 and 2 both are insufficient to get the value C-B..
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