As per Vips000 solution after you solve we get \(=|x|\)
now if we were given an additional constraint that X is positive then we can solve for the modulus right?
If we know that x is positive then we can solve the modulus and obtain \(|x|=x\), yes you're right.
But be careful, in this case both c and e would be correct
C). \(|x|\) => \(x\)
They are the same.
Hope it's clear
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