Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

It can not be E because x <> |x| for any negative value of x.

Hope it helps..

Well, I haven't understood completely. All i know from my knowledge that |a - b| = |b - a| So, as you have explained above |x-5|- |x-5| = 0 Now we are left with |-x| According to what i have read from the books, any absolute value whether negative or positive will come out as positive. For eg. |-5| = 5. This is the exact reason i selected E as the answer.

I must be missing one of the concepts. Can you please elaborate more on it. I didn't completely understand this statement "It can not be E because x <> |x| for any negative value of x."

It can not be E because x <> |x| for any negative value of x.

Hope it helps..

Well, I haven't understood completely. All i know from my knowledge that |a - b| = |b - a| So, as you have explained above |x-5|- |x-5| = 0 Now we are left with |-x| According to what i have read from the books, any absolute value whether negative or positive will come out as positive. For eg. |-5| = 5. This is the exact reason i selected E as the answer.

I must be missing one of the concepts. Can you please elaborate more on it. I didn't completely understand this statement "It can not be E because x <> |x| for any negative value of x."

Thanks & Regards Vinni

Two points that you are confused with: |-x| = |x| This is exactly same thing as you have mentioned: "All i know from my knowledge that |a - b| = |b - a|"

Now second point, x <> |x| for any negative number x.

Well, take for example x =-5 in this case, x= -5 and |x|=5 Are these 5 and -5 equal? no. That is x <> |x| for any negative number x.

Re: What is the value of |f(x)| - |g(x)| + |f(g(x)| ? [#permalink]

Show Tags

22 Nov 2012, 06:03

1

This post received KUDOS

Expert's post

greatps24 wrote:

Kudos Bunuel. Thanks for clarifying

One point: what if in answer choices we also have |-x| (and |x|)?

|-x| and |x| are equal, thus we cannot have both of them among answer choices. Consider this, can we have both 4 and 2^2 among answer choices? _________________

It can not be E because x <> |x| for any negative value of x.

Hope it helps..

Got a doubt...

f(g(x)| = |f(5-x)| = |5-x-5| =|-x| Why (5-x) is considered without Mod sign. Ideally it should have been |f(|5-x|)| = |(|5-x|)-5| If we simplify this we get two options |x-10| and |x|. Why this is not correct ??

It can not be E because x <> |x| for any negative value of x.

Hope it helps..

Got a doubt...

f(g(x)| = |f(5-x)| = |5-x-5| =|-x| Why (5-x) is considered without Mod sign. Ideally it should have been |f(|5-x|)| = |(|5-x|)-5| If we simplify this we get two options |x-10| and |x|. Why this is not correct ??

|f(g(x))| has only one modulus.

g(x)=5-x, thus |f(g(x))| = |f(5-x)|.

Next, since f(5-x) = 5-x-5=-x, then |f(5-x)| = |-x| = |x|.

Excellent posts dLo saw your blog too..!! Man .. you have got some writing skills. And Just to make an argument = You had such an amazing resume ; i am glad...

So Much $$$ Business school costs a lot. This is obvious, whether you are a full-ride scholarship student or are paying fully out-of-pocket. Aside from the (constantly rising)...

I barely remember taking decent rest in the last 60 hours. It’s been relentless with submissions, birthday celebration, exams, vacating the flat, meeting people before leaving and of...

Rishabh from Gyan one services, India had a one to one interview with me where I shared my experience at IMD till now. http://www.gyanone.com/blog/life-at-imd-interview-with-imd-mba/ ...