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# What is the value of j? (1) j + j = 2j (2) j^2 = (7.435)j^2

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What is the value of j? (1) j + j = 2j (2) j^2 = (7.435)j^2 [#permalink]  03 Nov 2005, 00:23
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What is the value of j?

(1) j + j = 2j
(2) j^2 = (7.435)j^2
SVP
Joined: 24 Sep 2005
Posts: 1893
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Kudos [?]: 139 [0], given: 0

Re: DS Algebra [#permalink]  03 Nov 2005, 01:50
GMATT73 wrote:
What is the value of j?

(1) j + j = 2j
(2) j^2 = (7.435)j^2

(1) 2j=2j --> all value of j are fine ---> insuff
(2) in case j= 0. (2) is correct
j <>0 --> 1= 7.435 , this is illogical
so from (2) we can find j= 0 ---> suff
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Location: India, Chennai
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Re: DS Algebra [#permalink]  03 Nov 2005, 04:00
GMATT73 wrote:
What is the value of j?

(1) j + j = 2j
(2) j^2 = (7.435)j^2

From 1 we get 2j = 2j this is true for all values of j, so insufficient.

From 2 we get 7.435J^2 - J^2 = 0
=> 6.435j^2 = 0 => j^2=0 or j = 0.

Hence B.
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1.
j=0: 0+0=2*0
j=1: 1+1=2*1
j=2: 2+2=2*2
All 3 values of j work -- insuf.

2.
j^2 = 7.435*j^2
this will only work if j=0 -- suff.

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