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In the question it is not mentioned that m is not equal to n If m=n=5 then the ratio is indefinite! Hence 2 is not suffucient and we need 1 to solve this (just to make sure that m<>n)

In the question it is not mentioned that m is not equal to n If m=n=5 then the ratio is indefinite! Hence 2 is not suffucient and we need 1 to solve this (just to make sure that m<>n)

Any comments?

M and N can't be equal because division by 0 would occur. Answer is B.

I do not remmember the source, but ETS does not take the x/0 equation at anytime. As this will lead to infinity (anything by zero is not valid). Hence, the above answer B is valid.

Perhaps, others can put some info they have obtained.
_________________

I was inclined to go ahead and put down 'B' for answer, but then I thought of testing possible values for m and n in (m^2-n^2) = 40
(m+n)(m-n) = 40
the only values I could come up with are:
(7+3)(7-3)=40

thisquestion is from ETS official guide 10 th edition

Folks,

I also chose C because of the m<>n thing
But OA is B
I guess the Q is poorly framed;
In most cases Qs clearly mention "m<>n" in cases where divide by zero is a possibility

The source of this Qusetion and Answer is from internet.

Rahul, If this Q is in OG, could you please check and tell us what the OA is in ETS OG?