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Re: What is the value of n in the equation - 25 + 19 + n = 5 ? [#permalink]
08 Oct 2012, 01:55

1

This post received KUDOS

Expert's post

SOLUTION

What is the value of n in the equation - 25 + 19 + n = s ?

(1) s = 2 --> - 25 + 19 + n = 2. We have a linear equation with one unknown, hence we can solve for it. Sufficient. (2) n/s = 4 --> s=n/4 --> - 25 + 19 + n = n/4. We have a linear equation with one unknown, hence we can solve for it. Sufficient.

Re: What is the value of n in the equation - 25 + 19 + n = 5 ? [#permalink]
08 Oct 2012, 02:09

St 1: Sufficient: Substitute S=2 in 25+19+n=2, Value of n can be found out from this linear equation. St 2: Sufficient: Substitute s=n/4 in 25+19+n=n/4, Value of n can be found out from this linear equation.

Re: What is the value of n in the equation - 25 + 19 + n = 5 ? [#permalink]
11 Oct 2012, 13:27

Expert's post

SOLUTION

What is the value of n in the equation - 25 + 19 + n = s ?

(1) s = 2 --> - 25 + 19 + n = 2. We have a linear equation with one unknown, hence we can solve for it. Sufficient. (2) n/s = 4 --> s=n/4 --> - 25 + 19 + n = n/4. We have a linear equation with one unknown, hence we can solve for it. Sufficient.

Answer: D.

Kudos points given to everyone with correct solution. Let me know if I missed someone. _________________

Re: What is the value of n in the equation - 25 + 19 + n = 5 ? [#permalink]
15 Oct 2012, 13:36

Expert's post

Bunuel wrote:

SOLUTION

What is the value of n in the equation - 25 + 19 + n = s ?

(1) s = 2 --> - 25 + 19 + n = 2. We have a linear equation with one unknown, hence we can solve for it. Sufficient. (2) n/s = 4 --> s=n/4 --> - 25 + 19 + n = n/4. We have a linear equation with one unknown, hence we can solve for it. Sufficient.

Answer: D.

Kudos points given to everyone with correct solution. Let me know if I missed someone.

D straight Bunuel but could someone think about n/s=4 that n and s can be both positive or negative ?? 16/4 = 4 or -16/-4 = 4 so is not safely to cross multiply S ?? or this concern regards questions in which < or > are involved ??'

Re: What is the value of n in the equation - 25 + 19 + n = 5 ? [#permalink]
15 Oct 2012, 14:28

Expert's post

carcass wrote:

Bunuel wrote:

SOLUTION

What is the value of n in the equation - 25 + 19 + n = s ?

(1) s = 2 --> - 25 + 19 + n = 2. We have a linear equation with one unknown, hence we can solve for it. Sufficient. (2) n/s = 4 --> s=n/4 --> - 25 + 19 + n = n/4. We have a linear equation with one unknown, hence we can solve for it. Sufficient.

Answer: D.

Kudos points given to everyone with correct solution. Let me know if I missed someone.

D straight Bunuel but could someone think about n/s=4 that n and s can be both positive or negative ?? 16/4 = 4 or -16/-4 = 4 so is not safely to cross multiply S ?? or this concern regards questions in which < or > are involved ??'

Thanks

You should be concerned about the signs only with inequalities. For equations you can safely cross-multiply. _________________

Re: What is the value of n in the equation - 25 + 19 + n = S ? [#permalink]
31 Dec 2012, 22:47

hello, for statement (2), what if

n=4 and s=1

then -25 + 19 + 4 = -2 but s=1 NOT GOOD

also consider if n=8 and s=2

then -25 + 19 + 8 = 2 and s = 2 GOOD

since it is possible to pick different sets of numbers that yield conflicting answers, shouldn't this statement alone be insufficient? (refer to OG13 DS#41 for comparison)

Re: What is the value of n in the equation - 25 + 19 + n = S ? [#permalink]
01 Jan 2013, 01:42

Expert's post

chekitsch wrote:

hello, for statement (2), what if

n=4 and s=1

then -25 + 19 + 4 = -2 but s=1 NOT GOOD

also consider if n=8 and s=2

then -25 + 19 + 8 = 2 and s = 2 GOOD

since it is possible to pick different sets of numbers that yield conflicting answers, shouldn't this statement alone be insufficient? (refer to OG13 DS#41 for comparison)

n=4 and s=1 do not satisfy - 25+19+n=s.

We have two equations: - 25+19+n=s and n/s=4. Solving gives n=8 and s=2. _________________

Re: What is the value of n in the equation - 25 + 19 + n = 5 ? [#permalink]
28 Oct 2013, 20:13

fameatop wrote:

Reducing Stem we get n = s + 6 1) s=2--> n=8 ---> Sufficient 2) s=n/4 --->Sufficient

Answer D

For the second statement: I know I should stop after knowing that it's a linear-with one unknown, I'm rusty on my math, how does this become

I get this, N/S=4 S=4N (multiply each side) (lost in this step) I did the following N=S+6 N=4N+6 -3N=6 3 3 N=-2, (should be positive)

Not sure how I got a negative, I guessed correctly, the second time i worked the problem. I'm not sure how the MGMAT guide states that the number becomes S=1/4N, maybe so it's not negative, it's placed with a fraction? Can someone refresh me with that concept. thanks.

Re: What is the value of n in the equation - 25 + 19 + n = 5 ? [#permalink]
29 Oct 2013, 01:22

Expert's post

selfishmofo wrote:

fameatop wrote:

Reducing Stem we get n = s + 6 1) s=2--> n=8 ---> Sufficient 2) s=n/4 --->Sufficient

Answer D

For the second statement: I know I should stop after knowing that it's a linear-with one unknown, I'm rusty on my math, how does this become

I get this, N/S=4 S=4N (multiply each side) (lost in this step) I did the following N=S+6 N=4N+6 -3N=6 3 3 N=-2, (should be positive)

Not sure how I got a negative, I guessed correctly, the second time i worked the problem. I'm not sure how the MGMAT guide states that the number becomes S=1/4N, maybe so it's not negative, it's placed with a fraction? Can someone refresh me with that concept. thanks.

Not sure I understand everything in your post but n/s = 4 means n = 4s (multiply both sides by s) not s = 4n.

Re: What is the value of n in the equation - 25 + 19 + n = 5 ? [#permalink]
29 Oct 2013, 06:44

Bunuel wrote:

selfishmofo wrote:

fameatop wrote:

Reducing Stem we get n = s + 6 1) s=2--> n=8 ---> Sufficient 2) s=n/4 --->Sufficient

Answer D

For the second statement: I know I should stop after knowing that it's a linear-with one unknown, I'm rusty on my math, how does this become

I get this, N/S=4 S=4N (multiply each side) (lost in this step) I did the following N=S+6 N=4N+6 -3N=6 3 3 N=-2, (should be positive)

Not sure how I got a negative, I guessed correctly, the second time i worked the problem. I'm not sure how the MGMAT guide states that the number becomes S=1/4N, maybe so it's not negative, it's placed with a fraction? Can someone refresh me with that concept. thanks.

Not sure I understand everything in your post but n/s = 4 means n = 4s (multiply both sides by s) not s = 4n.

Hope it helps.

I'm not sure how the MGMAT guide states that the number becomes S=1/4N, maybe so it's not negative, it's placed with a fraction? Can someone refresh me with that concept. Thank you for the other concept, I missed that small detail in trying to explain the problem.

Re: What is the value of n in the equation - 25 + 19 + n = 5 ? [#permalink]
29 Oct 2013, 06:47

Expert's post

selfishmofo wrote:

Bunuel wrote:

selfishmofo wrote:

For the second statement: I know I should stop after knowing that it's a linear-with one unknown, I'm rusty on my math, how does this become

I get this, N/S=4 S=4N (multiply each side) (lost in this step) I did the following N=S+6 N=4N+6 -3N=6 3 3 N=-2, (should be positive)

Not sure how I got a negative, I guessed correctly, the second time i worked the problem. I'm not sure how the MGMAT guide states that the number becomes S=1/4N, maybe so it's not negative, it's placed with a fraction? Can someone refresh me with that concept. thanks.

Not sure I understand everything in your post but n/s = 4 means n = 4s (multiply both sides by s) not s = 4n.

Hope it helps.

I'm not sure how the MGMAT guide states that the number becomes S=1/4N, maybe so it's not negative, it's placed with a fraction? Can someone refresh me with that concept. Thank you for the other concept, I missed that small detail in trying to explain the problem.

\(n = 4s\) --> \(s = \frac{n}{4}\) or \(\frac{1}{4}*n\) (it's not \(\frac{1}{4n}\)). _________________

Re: What is the value of n in the equation - 25 + 19 + n = S ? [#permalink]
05 May 2015, 13:22

Hello from the GMAT Club BumpBot!

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Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

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