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VP
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What is the value of p of x^2+6x+p? 1) x^2+6x+p= -3 2) [#permalink]
 11 Dec 2005, 06:38
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What is the value of p of x^2+6x+p?
1) x^2+6x+p=[(x+r)^2]-3
2) x^2+6x+p=(x+m)(x+n)
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Director
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p,m,n,r are all different.
Seems like E)
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Intern
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Statement 1: Since 3 variables (x, p, r) are present, we need 3 different equations, but we only have 2 equations.
Statement 2: Since 4 variables (x, p, m, n) are present, we need 4 different equations.
Combined: Since 5 different (x, p, r, m, n) variables are present, we need to have atleast 5 different equations.
Answer = E
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VP
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Please give it one more thought.
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VP
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is it A?
S1:
x^2+6x+p=[(x+r)^2]-3 or
x^2+6x+ (p + 3) = [(x+r)^2]
to be perfect square (x+3)^2,
p+3 should be 9
or p = 6
S2:
x^2+6x+p=(x+m)(x+n) or
x^2+6x+p= x^2 + (m+n)x + mn
or:
m+n = 6
mn = p
as we do not know value of m,n,p
insufficient
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agree with duttsit. A is the answer.
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VP
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duttsit wrote: is it A?
S1:
x^2+6x+p=[(x+r)^2]-3 or
x^2+6x+ (p + 3) = [(x+r)^2]
to be perfect square (x+3)^2,
p+3 should be 9
or p = 6
S2:
x^2+6x+p=(x+m)(x+n) or
x^2+6x+p= x^2 + (m+n)x + mn
or:
m+n = 6
mn = p
as we do not know value of m,n,p
insufficient
Good job, duttist.
The Answer is (A).
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