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# What is the value of the integer n? (1) n(n+2) =15 (2)

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VP
Joined: 26 Apr 2004
Posts: 1225
Location: Taiwan
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What is the value of the integer n? (1) n(n+2) =15 (2) [#permalink]  28 Dec 2004, 08:04
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(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
What is the value of the integer n?

(1) n(n+2) =15

(2) (n+2)^n = 125
Director
Joined: 29 Oct 2004
Posts: 865
Followers: 2

Kudos [?]: 63 [0], given: 0

(B)

(A): n(n+2)=15
n^2+2n-15=0
(n-3)(n+5)=0
n=3,-5
Nope

(B)
n:integer
n=3
Manager
Joined: 29 Jul 2004
Posts: 62
Followers: 1

Kudos [?]: 0 [0], given: 0

I also got B, but was wondering if there is a better way to solve the 2nd equation than by trying different integers, which was what I did.
VP
Joined: 25 Nov 2004
Posts: 1495
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Kudos [?]: 38 [0], given: 0

Re: DS0534 [#permalink]  30 Dec 2004, 18:01
chunjuwu wrote:
What is the value of the integer n?

(1) n(n+2) =15

(2) (n+2)^n = 125

http://www.gmatclub.com/phpbb/viewtopic ... ght=#72451
VP
Joined: 18 Nov 2004
Posts: 1442
Followers: 2

Kudos [?]: 20 [0], given: 0

"B" it is.

Todd the 2nd one can be solved quickly as (n+2)^n = 125 or 5^3 or (3+2)^3

If u see only n = 3 is a solution here
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