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What is the value of │x + 7│? (1) │x + 3│= 14 (2) (x + 2)2 = 169

OA must be wrong here.

(1) \(|x+3|=14\) --> \(x=11\) or \(x=-17\), so \(|x+7|=18\) or \(|x+7|=10\); (2) \((x+2)^2=169\) --> \(x=11\) or \(x=-15\), so \(|x+7|=18\) or \(|x+7|=8\);

What is the value of │x + 7│? (1) │x + 3│= 14 (2) (x + 2)2 = 169

OA must be wrong here.

(1) \(|x+3|=14\) --> \(x=11\) or \(x=-17\), so \(|x+7|=18\) or \(|x+7|=10\); (2) \((x+2)^2=169\) --> \(x=11\) or \(x=-15\), so \(|x+7|=18\) or \(|x+7|=8\);

(1)+(2) \(|x+7|=18\). Sufficient.

Answer: C.

Many thanks again ... I this the OA I have are definitly wrong

What is the value of │x + 7│? (1) │x + 3│= 14 (2) (x + 2)2 = 169

I feel the answer should be E as in both the option we will get 2 different values of x.

Am I going wrong?

STAT1 |x+3| = 14 will give you two solutions x+3 = 14 and x+3 = -14 x = 11, -17 SO, NOT SUFFICIENT

STAT2 (x+2)^2 = 169 x+2 = +-13 x = -15, 11 So, NOT SUFFICIENT

If you take STAT1 and STAT2 together then there is only one value of x which satisfies both the Statements and is x=11 so, x=11 Hence, Answer will be C

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