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Re: What is the value of x ? [#permalink]
07 Jun 2012, 22:57

1

This post received KUDOS

macjas wrote:

What is the value of x ?

(1) x^3 = 6x − x^2

(2)14x = x^3 + 5x^2

Statement (1)

x^3 = 6x - x^2

by factoring we have: x (x + 3) ( x - 2) = 0 so x = 0, x = - 3 and x = 2 (ins.)

Statement (2)

14x = x^3 + 5x^2

by factoring we have: x (x + 7) (x - 2) = 0 so x = 0, x = -7 and x = 2 (ins.)

Statement (1) AND (remember in Mathematics "and" means intersection, in layman's term: what is the common in both statement?) Statement (2)

x = 0 as well as x = 2

So still insufficient because we have two values of x

Hope I helped _________________

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Re: What is the value of x ? [#permalink]
07 Jun 2012, 23:00

2

This post received KUDOS

Hi,

to find the value of x,

using (1) \(x^3 = 6x-x^2\) or \(x^3 - 6x + x^2=0\) or \(x(x^2+x-6)=0\) or \(x(x+3)(x-2)=0\) or \(x=-3, 0, 2\), no unique value of x. Insufficient.

using (2) \(14x = x^3 + 5x^2\) or \(x^3 + 5x^2-14x=0\) or \(x(x^2+5x-14)=0\) or \(x(x+7)(x-2)=0\) or \(x=-7, 0 , 2\), no unique value of x. Insufficient.

Re: What is the value of x ? [#permalink]
29 Aug 2012, 03:28

Hi, was just wondering if we could solve it like this: From 1) x^3 = 6x + x^2 From 2) x^3 = 14x – 5x^2 From 1) and 2), we get 6x – x^2 = 14x – 5x^2 Solving the above, we get, x = 2 Hence, C

Re: What is the value of x ? [#permalink]
27 Feb 2013, 18:10

1

This post received KUDOS

reetskaur wrote:

Hi, was just wondering if we could solve it like this: From 1) x^3 = 6x + x^2 From 2) x^3 = 14x – 5x^2 From 1) and 2), we get 6x – x^2 = 14x – 5x^2 Solving the above, we get, x = 2 Hence, C

Hi, Even if you solve by the above method you again get two values of x. 4x^2+6x-14x=0 x(4x-8) = 0 x = 0, 2 so Insufficient

Re: What is the value of x ? [#permalink]
30 Dec 2014, 07:48

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