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What is the value of x?

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Re: What is the value of x? [#permalink] New post 01 Dec 2012, 20:31
Yeah....got it guys.
Thanx Bull and AbhiJ
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Re: What is the value of x? [#permalink] New post 02 Dec 2012, 05:59
Hii Shan.
Replying to your PM, I guess you are also making the same silly and also much disastrous mistake.
Expand carefully and notice the difference between the equations.

Moreover, If you are applying the same method of mine then after getting the final values, put them in the respective equations. The equation won't satisfy.
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Re: What is the value of x? [#permalink] New post 02 Dec 2012, 06:50
Marcab wrote:
Hii Shan.
Replying to your PM, I guess you are also making the same silly and also much disastrous mistake.
Expand carefully and notice the difference between the equations.

Moreover, If you are applying the same method of mine then after getting the final values, put them in the respective equations. The equation won't satisfy.


Yes Marcab i got solution that VIPS and others stated...
sorry for the offense VIPS :lol:

but i'm eager enough to know about my mistake... (or even the way marcab did) :roll:

I donno where i did mistake in substitution method :?
But i'm getting solution in solving two equation :shock: .....
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Re: What is the value of x? [#permalink] New post 02 Dec 2012, 23:00
shanmugamgsn wrote:
Marcab wrote:
Hii Shan.
Replying to your PM, I guess you are also making the same silly and also much disastrous mistake.
Expand carefully and notice the difference between the equations.

Moreover, If you are applying the same method of mine then after getting the final values, put them in the respective equations. The equation won't satisfy.


Yes Marcab i got solution that VIPS and others stated...
sorry for the offense VIPS :lol:

but i'm eager enough to know about my mistake... (or even the way marcab did) :roll:

I donno where i did mistake in substitution method :?
But i'm getting solution in solving two equation :shock: .....


No offence taken bro! Definitely I screwed enough to raise such doubts on my tips and solutions :P (remember to sleep well before your exam :-D )

To know where you/marcab went wrong, you need to focus on basic concept of solving linear equations. You MUST be able to eliminate one of the variables. some do it with substitution and some using addition/substraction- whichever is easier in the given context.

For this question: if you are getting a soltion- that is correct. Ans must be C not E for the set of equations.
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Re: What is the value of x? [#permalink] New post 06 Dec 2012, 22:54
gmatbull wrote:
What is the value of x?

(1) x/7 + 5y = 109
(2) 175y = 763(5 - x)


Responding to a pm:

When you have two distinct linear equations in two variables, you can solve for the two variables. In other words, a linear equation in 2 variables represents a line. When you have two non-parallel distinct lines, you get one unique point of intersection of the two lines. i.e. there is a single value of x and y which satisfies both equations.

It is obvious here that both statements alone are not sufficient.

Taking both together,
x/7 + 5y =109 => x + 35y = 109*7
175y = 763(5 - x) You can see that when you get x on the left hand side, the co-efficient of x (which is 763) is much larger than the co-efficient of y (which is 175). In the first equation, the coefficient of x (which is 1) is smaller than the coefficient of y (which is 35). So you cannot reduce the equation in a way that the ratio of co-efficients of x will be equal to ratio of co-efficients of y. Hence there will be a unique solution. Answer will be (C)


OE discusses the case where 'the ratio of co-efficients of x will be equal to ratio of co-efficients of y'. One of the two equations have been given incorrectly in the question.

Check out these posts for a discussion of these concepts:

http://www.veritasprep.com/blog/2011/08 ... nd-points/
http://www.veritasprep.com/blog/2011/08 ... and-lines/
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Re: What is the value of x?   [#permalink] 06 Dec 2012, 22:54
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