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# What is the value of │x + 7│?

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What is the value of │x + 7│? [#permalink]

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17 Sep 2007, 11:30
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What is the value of │x + 7│?
(1) │x + 3│= 14
(2) (x + 2)^2 = 169
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17 Sep 2007, 11:54
stmt 1: 2 possibilities
stmt 2: 2 possibilities

using both pick the common factor.
C
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17 Sep 2007, 12:29
|x+7| = ?

statement 1

x+3 = 14 or -x-3 = 14

x = 11 or x = -17

insufficient

statement 2

(x+2)^2 = 169

x^2+4x+4 = 169

x^2+4x-165 = 0

(x-11)(x+15) = 0

x= 11 or x = -15

insufficient

both statements

x = 11

sufficient

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Re: DS - Set 6, Q7 [#permalink]

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17 Sep 2007, 12:52
gluon wrote:
What is the value of │x + 7│?
(1) │x + 3│= 14
(2) (x + 2)^2 = 169

-x-3=14 ---> x=-17

x+3=14 x=11

Insuff.

2.
x^2+4x+4=169 x^2+4x-165 (x+15)(x-11) To find these two numbers just realize that 165 has to have 5 as a factor so one of the numbers is going to have a 5 as the units digit.

so x=15, or x=11.

Insuff.

Together x=11.

For s2 be careful not to just squaroot everything. You only get one value this way, 11. Thats what I did =(.

Ans C.
Re: DS - Set 6, Q7   [#permalink] 17 Sep 2007, 12:52
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