tejal777 wrote:

could you please elaborate a bit?

How did the right-hand side change from -x to mod x?

Right hand did not change from -x to mod |x|, rather left hand side itself is equal to |x|.

Okay, consider this: what is the value of

\sqrt{5^2}? It is {-5,5} That means it is |5|.

So

\sqrt{x^2}=|x|.

Now

|x| = -x. So x = 0 or negative. Thus the value of x cannot be determined.

Considering statement 1 and 2 together you can find out that value of x is -3.

One IMPORTANT CLUE to remember: In DS, both statement 1 and statement 2 ALWAYS RETURN THE SAME RESULT. So when in doubt just check the result from other statement. As statement 1 in this case represents the value of x as either 3 or -3, statement 2 CANNOT return the value of x as ZERO.

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