krishan wrote:

If x and y are non-zero integers and |x| + |y| = 32, what is xy?

(1) -4x – 12y = 0

(2) |x| – |y| = 16

the 1st is clearly sufficient.

x=-3y; if x<0 y>0 and if x>0, y<0. Either case xy<0. Solving euqation we get xy.

(2)=> let x and y>0.

x+y=32

x-y=16 i.e. x=24 and y=8. So xy is found for x and y >0.

Now, x and y<0

-x-y=32

-x+y=16 i.e. x=-24 and y=-8 again xy is found for x and y both less than 0.

if x> and y<0,

x-y=32

x+y=16 so, x=24 and y=-8.

But thee is no way to say whether xy is greater or less than zero.

Hence, A.

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tusharvk