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# What is the value of y? (1) 3|x2(readx square) 4| = y 2 (2)

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Manager
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What is the value of y? (1) 3|x2(readx square) 4| = y 2 (2) [#permalink]

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03 Jul 2007, 18:21
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What is the value of y?

(1) 3|x2(readx square) – 4| = y – 2

(2) |3 – y| = 11

Manager
Joined: 12 Apr 2007
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03 Jul 2007, 19:17
E

S1: Two variables, therefore no set value for y, insufficient

S2: y can be -8 or 14, insufficient

S1+S2: No help as S1 does not help in choosing between -8 and 14
Director
Joined: 09 Aug 2006
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03 Jul 2007, 21:40
dreamgmat1 wrote:
What is the value of y?

(1) 3|x2(readx square) – 4| = y – 2

(2) |3 – y| = 11

Yup ... E.. Both stmnts r insuff..
Director
Joined: 18 Jul 2006
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03 Jul 2007, 22:40
Should be C.
(1) INSUFF
(2) gives y = 14 or -8 INSUFF

From (1) and (2)
3|x^2-4| = 14-2 or -8-2

|x^2-4| has to be +ve, so y=14, SUFF
Director
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04 Jul 2007, 00:33
Juaz wrote:
Should be C.
(1) INSUFF
(2) gives y = 14 or -8 INSUFF

From (1) and (2)
3|x^2-4| = 14-2 or -8-2

|x^2-4| has to be +ve, so y=14, SUFF

Yes. It is C.. thanks for the explanation Juaz..
Director
Joined: 14 Jan 2007
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04 Jul 2007, 04:27
Himalayan wrote:
dreamgmat1 wrote:
What is the value of y?

(1) 3|x2(readx square) – 4| = y – 2

(2) |3 – y| = 11

C.

I am observing since last few days that you solve the problem correctly, but don't give detailed solution....is this the part of strategy?
SVP
Joined: 01 May 2006
Posts: 1797
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04 Jul 2007, 04:42
(C) for me too

y= ?

From 1
3|x^2– 4| = y – 2

X and Y could be many numbers. But y >= 2 as abs( ...... ) >= 0.

INSUFF.

From 2
|3 – y| = 11

o If 3-y >= 0, then:
3 – y = 11
<=> y = -8

o If 3-y < 0, then:
-(3 – y) = 11
<=> y = 14

So, y could be -8 or 14.

INSUFF.

Both 1 and 2
We know that:
o y >= 2
and
o y = -8 or y = 14

Thus, y = 14.

SUFF.
Manager
Joined: 23 May 2007
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04 Jul 2007, 08:34
Thanks Fig for the perfect explanation.The OA is C.
Director
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04 Jul 2007, 11:51
vshaunak@gmail.com wrote:
Himalayan wrote:
dreamgmat1 wrote:
What is the value of y?

(1) 3|x2(readx square) – 4| = y – 2

(2) |3 – y| = 11

C.

I am observing since last few days that you solve the problem correctly, but don't give detailed solution....is this the part of strategy?

yah, you are right. my strategy is to give others chance to make their explanation so that we all can learn different approaches and opinions. This also enhances more opinions.

Some mistirious questions need to be waited for a while for more effort by others.

its indeed a very good question.
Re: Another Mod DS   [#permalink] 04 Jul 2007, 11:51
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