shanmugamgsn wrote:

What is the value of \(y\)?

(1)\(y^3+2y=y+2y^2\)

(2)\(y^2=y\)

My choice was A..

I did this way can any one correct me if im wrong??

(2) INSUFFICIENT :

\(y^2-y=0\)

\(y(y-1)\)

So \(y=0\) or \(y=1\)

(1) i felt this is SUFFICIENT:

\(y^3+2y=y+2y^2\)

divide by y on both sides

\(y^2+2=1+2y\)

\(y^2-2y+1=0\)

\((y-1)^2=0\)

So solution will be \(y=1\)

Is there any mistakes in my calculation?

If y this soln is wrong???

_________________

GMAT - Practice, Patience, Persistence

Kudos if u like