shanmugamgsn wrote:

What is the value of y?

(1)y^3+2y=y+2y^2

(2)y^2=y

My choice was A..

I did this way can any one correct me if im wrong??

(2) INSUFFICIENT :

y^2-y=0 y(y-1)So

y=0 or

y=1(1) i felt this is SUFFICIENT:

y^3+2y=y+2y^2 divide by y on both sides

y^2+2=1+2y y^2-2y+1=0 (y-1)^2=0So solution will be

y=1Is there any mistakes in my calculation?

If y this soln is wrong???

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