What is the value of y?
My choice was A..
I did this way can any one correct me if im wrong??
(2) INSUFFICIENT : y^2-y=0 y(y-1)
(1) i felt this is SUFFICIENT: y^3+2y=y+2y^2
divide by y on both sides y^2+2=1+2y y^2-2y+1=0 (y-1)^2=0
So solution will be y=1
Is there any mistakes in my calculation?
If y this soln is wrong???
At first glance of the equation given in Statement 1, you should be able to see that 0 is a solution to the equation. Every expression contains a y term and hence 0 will satisfy the equation. Your first step is dividing by y. Since y is an unknown variable, that step cannot be allowed. As the famous mems of the internet go No one except Chuck Norris can divide by 0.